Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.
Answer:
1.4
Step-by-step explanation:
Sample size: 3
Lowest value: 2.89
Highest value: 4.29
Range: 1.4
formula for calculating the range:
Range = maximum(x_i) - minimum(x_i)
where x_i represents the set of values.
Answer:
106
Step-by-step explanation:
