Answer:
C.) 2![\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D)
Step-by-step explanation:
<em>You must use the pythagorean theorem</em>
the distance on the x axis (or a) is 6
the distance on the y axis (or b) is 10
= 136
= 2![\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D)
Answer:
(x+4)(6x^2 - 7)
Step-by-step explanation:
Focus on the first 2 terms first and on the second 2 terms last:
6x^3 + 24x^2 = 6x^2(x+4)
-7x-28 = -7(x+4)
We see that the factor (x+4) is common to both pairs: common to the first 2 terms and common to the last 2 terms.
Thus,
6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)
Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).
Answer:
39 points
Step-by-step explanation:
Your school's football team scored 49 points.
Your team's score is 19 points more than the opponents score
The opponent score is represented as S
Since the total points that was scored is 49 and your team score is 19 then the equation can be written as follows
S+ 19= 49
Solve for S
S= 49-19
S= 30
Hence the opponent's score is 30 points
4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
Answer:37 and half hrs
Step-by-step explanation:
This is what I get
Myra: 50/2= 25 bulbs/hr.
Francis: 45/3= 15 bulbs/ hr
25+15= 40/hr. Together per hr
Need to find 150 bulbs how many hrs
40/1=150/t
40t=150
T= 150/4
T= 37.5
37hrs and 1/2