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valkas [14]
3 years ago
8

#27 how do you find the variables in the triabgle?

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

x * y * 4 * 6 =

xy * 24 =

24x + 24y

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Will mark as brainiest (Must show work)
kirza4 [7]

Answer:

m∠CAB = 40°

Step-by-step explanation:

DAC = 99

DAB = 59

B is inside DAC, and so is DAB. So CAB must add to 59 to get to 99, nothing over that because it's inside DAC.

So 99 - 59 = 40

CAB must be 40°

That's all I can say for now. Hope this helps and a thank won't hurt! :)

3 0
2 years ago
According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mou
Anon25 [30]

 Let X be a discrete binomial random variable.
 Let p = 0.267 be the probability that a person does not cover his mouth when sneezing.
 Let n = 18 be the number of independent tests.
 Let x be the number of successes.
 So, the probability that the 18 individuals, 8 do not cover their mouth after sneezing will be:

 a) P (X = 8) = 18! / (8! * 10!) * ((0.267) ^ 8) * ((1-0.267) ^ (18-8)).
 P (X = 8) = 0.0506.

 b) The probability that between 18 individuals observed at random less than 6 does not cover their mouth is:

 P (X = 5) + P (X = 4) + P (X = 3) + P (X = 2) + P (X = 1) + P (X = 0) = 0.6571.

 c) If it was surprising, according to the previous calculation, the probability that less than 6 people out of 18 do not cover their mouths is 66%. Which means it's less likely that more than half of people will not cover their mouths when they sneeze.
4 0
2 years ago
Sandra has 1/2 of cup of sugar. She needs 3/4 of a cup of sugar to complete a recipe. What fraction of the required amount does
ValentinkaMS [17]
Example: Set up proportions.

3/4 cups → 1 batch
x cups → 2 batches

x = 2(3/4) = 6/4 = 1 1/2 cups

3/4 cups → 1 batch
y cups → 9 batches

y = 9(3/4) = 6 3/4 cups
7 0
2 years ago
Geometry problem help!<br><br> Please refer to the image below...
Vinil7 [7]

Answer:

A. 1/3

B. √10

C. -1, 1

D. √8, 6

E. congruent and opposite pairs parallel

F. perpendicular, not congruent

G. rhombus, explanation below

Step-by-step explanation:

Hey there! I'm happy to help!

-----------------------------------------------------------------

A.

Slope is the rise over the run. Let's look at F to G.

We are going from -1 to 2 on our x-axis (run), so our run is 3 units.

Our rise is 1 unit as we go from 2 to 3 on the y-axis.

slope=\frac{rise}{run} =\frac{1}{3}

This slope is the same for all of the sides.

-----------------------------------------------------------------

B.

We will use the distance formula (which is basically just the Pythagorean Theorem) to calculate the length of each side. Let's go between F and G again, but this distance is the same for all the sides.

\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-1,2)\\\\(x_2,y_2)=(2,3)\\\\\\\sqrt{(2+1)^2+(3-2)^2 } \\\\\sqrt{(3)^2+(1)^2 }\\\\\sqrt{9+1 }\\\\\sqrt{10}

-----------------------------------------------------------------

C.

The diagonals are the lines that connect the non-adjacent vertices.

Our two diagonals are FH and GE.

-----------------------------

<u>FH</u>

We go from x-value -1 to 1 from F to H, so our run is 2.

We go from y-value 2 to 0. so our rise is -2.

slope=\frac{rise}{run} =-\frac{2}{2} =-1

-----------------------------

<u>GE</u>

We go from x-value -2 to 2 from E to G, so our run is 4.

We go from y-value -1 to 3. so our rise is 4.

slope=\frac{rise}{run} =\frac{4}{4} =1

-----------------------------------------------------------------

D.

Let's use the distance formula on each of our diagonals.

-----------------------------

<u>FH</u>

<u />\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-1,2)\\\\(x_2,y_2)=(1,0)\\\\\\\sqrt{(1+1)^2+(0-2)^2 } \\\\\sqrt{(2)^2+(-2)^2 }\\\\\sqrt{4+4 }\\\\\sqrt{8}<u />

-----------------------------

<u>GE</u>

\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-2,-1)\\\\(x_2,y_2)=(2,3)\\\\\\\sqrt{(2+2)^2+(3+1)^2 } \\\\\sqrt{(4)^2+(4)^2 }\\\\\sqrt{16+16 }\\\\\sqrt{36}\\\\6

-----------------------------------------------------------------

E.

They are congruent as they all have the same length (√10) and the opposite sides are parallel as they have the same slope (1/3)

-----------------------------------------------------------------

F.

They are perpendicular diagonals as their slopes are negative reciprocals (1 and -1), and they are not congruent as they have different lengths (√8 and 6).

-----------------------------------------------------------------

G.

<u>Parallelogram-</u> quadrilateral with opposite pairs of parallel sides.

<u>Rhombus-</u> a parallelogram with four equal sides

<u>Square-</u> a rhombus with four right angles

We can see that this is a parallelogram as we saw that the opposite sides are parallel due to having the same slope, and the perpendicular diagonals show that as well. This is also a rhombus because if we use that distance formula on all the sides, it will be the same. It is not a square though because it does not have four right angles, so this is a rhombus.

-----------------------------------------------------------------

Have a wonderful day and keep on learning!

8 0
2 years ago
X &lt; 36 and x &gt; -36<br>x &lt; 36 or x&gt;-36<br>x&lt; 36 or x &gt; 0<br>x &lt; 36 and x &gt; 0​
hjlf

Answer:

D,x < 36 and x > 0, negative number cannot be in sq.root

3 0
3 years ago
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