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kolezko [41]
2 years ago
6

Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.​

Chemistry
2 answers:
zhuklara [117]2 years ago
7 0

The best way is add alcohol .

The common way is that decrease the atmospheric pressure .

This will work as per Boyles law ,and boiling point can be decreased.

but it has few restrictions

  • You can't decrease pressure simply at normal conditions
  • For decreasing pressure you have to go hill tops .

Hence there is a spare way

  • Add alcohol

General alcohols like ethanol,butanol can decrease the boiling point of water

slava [35]2 years ago
4 0

It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.

<h3>Concept :</h3>

To boil water at 95°C, decrease the atmospheric pressure.

At 105°C, the water will be boiling quickly than normal at 100°C.

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A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =
never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

ln\frac{k2}{k1} = 4,257

\frac{k2}{k1} = 70,593

{k2} = 9,53x10^3 s^{-1}

<em>k ≈ 9,56x10³ s⁻¹</em>

I hope it helps!

5 0
3 years ago
85% of what number is 17? EXPLAIN
vitfil [10]

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85% of 20 is 17

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You can multiply 85% and 20 or subtract 85% from 20.

5 0
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AleksAgata [21]
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