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4 years ago

15° 25 2p 35"

Chemistry

1 answer:

nataly862011 [7]4 years ago

6 0

B. Lower elements have more energy levels

Explanation:

Ionization energy decreases down the group because lower elements have more energy levels. Therefore, the pull of the nucleus on the outermost shell electrons is not so great.

Ionization energy is the energy required to remove an electron from an atom.
It is a measure of the readiness of an atom to lose an electron.
Down a group or family, atomic radius increases due to addition of more electronic shells or energy levels.
As the atomic radius becomes larger, the ionization energy reduces.
This is because of the increased shielding/screening effect of inner shell electrons on the electron to be removed from the nuclear attraction.
This way, its takes a lesser amount of energy to remove them as shielding effects increases down the group.

Learn more:

ionization energy brainly.com/question/1971327

#learnwithBrainly

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Refer to the periodic table tool and write the electron configurations of the following elements in both long and short terms

ahrayia [7]

Answer:-

Carbon

[He] 2s2 2p2

1s2 2s2 2p2.

potassium

[Ar] 4s1.

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:-

For writing the short form of the electronic configuration we look for the nearest noble gas with atomic number less than the element in question. We subtract the atomic number of that noble gas from the atomic number of the element in question.

The extra electrons we then assign normally starting with using the row after the noble gas ends. We write the name of that noble gas in [brackets] and then write the electronic configuration.

For carbon with Z = 6 the nearest noble gas is Helium. It has the atomic number 2. Subtracting 6 – 2 we get 4 electrons. Helium lies in 1st row. Starting with 2, we get 2s2 2p2.

So the short term electronic configuration is [He] 2s2 2p2

Similarly, for potassium with Z = 19 the nearest noble gas is Argon. It has the atomic number 18. Subtracting 19-18 we get 1 electron. Argon lies in 3rd row. Starting with 4, we get 4s1.

So the short electronic configuration is [Ar] 4s1.

For long term electronic configuration we must write the electronic configuration of the noble gas as well.

So for Carbon it is 1s2 2s2 2p2.

For potassium it is 1s2 2s2 2p6 3s2 3p6 4s1

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3 years ago

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3 years ago

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3 years ago

Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction: 2 CO(g) + O2(g) → 2 CO2(g)∆H for this react

MrMuchimi

Answer : The amount of heat released would be, (3) 811.68 kcal

Explanation : Given,

Moles of carbon monoxide = 12.0 mole

Enthalpy change = -135.28 kcal

The given balanced chemical reaction is,

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

From the balanced chemical reaction we conclude that,

As, 2 moles of carbon monoxide react to release heat = 135.28 kcal

So, 12.0 moles of carbon monoxide react to release heat = $\frac{12.0}{2}\times 135.28kcal=811.68kcal$

Thus, the amount of heat released would be, 811.68 kcal

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4 years ago

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elena-14-01-66 [18.8K]

Is this an actual question?

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