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3 years ago

15° 25 2p 35"

Chemistry

1 answer:

nataly862011 [7]3 years ago

6 0

B. Lower elements have more energy levels

Explanation:

Ionization energy decreases down the group because lower elements have more energy levels. Therefore, the pull of the nucleus on the outermost shell electrons is not so great.

Ionization energy is the energy required to remove an electron from an atom.
It is a measure of the readiness of an atom to lose an electron.
Down a group or family, atomic radius increases due to addition of more electronic shells or energy levels.
As the atomic radius becomes larger, the ionization energy reduces.
This is because of the increased shielding/screening effect of inner shell electrons on the electron to be removed from the nuclear attraction.
This way, its takes a lesser amount of energy to remove them as shielding effects increases down the group.

Learn more:

ionization energy brainly.com/question/1971327

#learnwithBrainly

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<h3><em>Further explanation</em></h3>

Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.

If O is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

$\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}$

Equalization of chemical reaction equations can be done using variables.

Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Methana combustion reaction

CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)

We give the most complex compounds, namely Methane, we give the number 1

So the reaction becomes

CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)

C atom on the left 1, right b, so b = 1

H atom on the left 4, right 2c, so 2c = 4 ---> c = 2

Atom O on the left 2a, right 2b + c, so 2a = 2b + c

2a = 2.1 + 2

2a = 4

a = 2

The equation becomes:

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Keywords: methane, combustion, hydrocarbons, equalization of reaction equations

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