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BabaBlast [244]
3 years ago
6

Find the average atomic mass of neon, given the atomic masses and relative abundance of its three isotopes.

Chemistry
1 answer:
Lyrx [107]3 years ago
6 0
<span>19.992*0.9048+20.993*0.0027+21.991+0.0925 = </span><span> 20.1797 amu (C)</span>
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R is the midpoint of FG.<br><br> FR = 26 find RG
vichka [17]

Answer:

52

Explanation:

This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG

7 0
2 years ago
Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

  • To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
  • Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

5 0
3 years ago
Calculate the cell potential at 25oC under the following nonstandard conditions: 2MnO4-(aq) + 3Cu(s) + 8H+(aq) ⟶ 2MnO2(s) + 3Cu2
baherus [9]

Answer:

1.346 v

Explanation:

1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

(oxidation) Cu_{(s)} →Cu^{2+}_{(aq)} +2e E°=0.337 v

(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

5 0
2 years ago
A qué llamamos fluido en reposo
Svetach [21]

Answer:

Lo llamas hidrostática

Explanation:

7 0
2 years ago
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Name the 3 seperate metals group
umka21 [38]

Akali Metals

Akali-Earth Metals

and Other Metals

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