Answer:
Yes.
Step-by-step explanation:
Although there is not much info on this question, if you were to assume that there are 3 different answers or 3 different methods of solving that problem, it is definitey possible to assume that this is possible.
Answer: she combined the constants incorrectly in the last step.... i just got it right on the test
Let the two integers be x and x+1
(x+1)^2-x^2=21
x^2+2x+1-x^2=21
2x+1=21
2x=20
x=10
then x=10, x+1
10+1=11
the two integers are 10, 11
A1 = first term = 4
a2 = second term = a1+5 = 4+5 = 0
a3 = third term a1 + 5 + 5 = a1 + 5(n-1), where n is the subscript that represents which term we're discussing.
an=4+5(n-1).
Is this correct? Let's check it and find out.
What is your prediction for a2? Here, n = 2. Then a2 = 4+5(2-1), or 4+5, or 9. That agrees with the given sequence rule.
Thus, the 250th term would be 4+5(250-1). Evaluate this, please.
5 hrs 45 min + 5hrs 45 min
(5 + 5)hrs + (45+45)min
10 hrs + 90 min
we can write it as
11 hrs 30 min
