Answer:
malleable
Explanation:
able to be bended into shape
17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
=
its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
» 
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton

Now,, from eq(2) toto
1/1:15 = 
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
Learn more about diffuse here
brainly.com/question/3266850
#SPJ9
Answer:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Explanation:
Given data:
Energy evolved when 1 mole of CO react = 283 Kj
Energy evolved when 2 mole of CO react = ?
Solution:
Chemical equation:
2CO + O₂ → 2CO₂
It is given when one mole of CO react with oxygen 283 KJ energy is produced.
When 2 mole react,
2 ×-283 kj = -566 kj
Thermal equation:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Because it can be balanced in an infinite number of ways so it would need to be rewritten in a simpler form.