Answer:
i am pretty sure the answer is a
Explanation: because the airplane's flight time has to be the independent variable for it to affect the dependent variable that is the speed of how fast the airplane is going.
Yes, Titan is bigger than Mercury. So basically, it's true.
The mass of the water in the container given the data from the question is 22.5 g
<h3>Data obtained from the question</h3>
- Mass of cold lead (M) = 54.3 g
- Temperature of lead (T) = 384.4 K
- Temperature of water (Tᵥᵥ) = 291.2 K
- Equilibrium temperature (Tₑ) = 297.6 K
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gK
- Specific heat capacity of lead (C) = 0.128 J/gK
- Mass of water (Mᵥᵥ) = ?
<h3>How to determine the mass of water </h3>
Heat loss = Heat gain
MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
54.3 × 0.128 (384.4 – 297.6) = Mᵥᵥ × 4.184(297.6 – 291.2)
6.9504 × 86.8 = Mᵥᵥ × 4.184 × 6.4
Divide both side by 4.184 × 6.4
Mᵥᵥ = (6.9504 × 86.8) / (4.184 × 6.4)
Mᵥᵥ = 22.5 g
Learn more about heat transfer:
brainly.com/question/6363778
#SPJ1
<h3>
Answer:</h3>
Al₂(SO₄)₃
<h3>
Explanation:</h3>
We are given percentage composition of elements in a compound;
- Aluminium is 15.77%
- Sulfur is 28.11 %
- Oxygen is 56.12%
We are required to calculate the empirical formula of the compound.
- Assuming the mass of the compound is 100 g then the masses of the elements is;
Aluminium = 15.77 g
Sulfur = 28.11
Oxygen = 56.12
We can determine the number of moles of each;
Moles of Aluminium = 15.77 g ÷ 26.98 g/mol
= 0.585 moles
Moles of sulfur = 28.11 g ÷ 32.07 g/mol
= 0.877 moles
Moles of Oxygen = 56.12 g ÷ 16.0 g/mol
= 3.5075 moles
- But, the empirical formula is the simplest whole number ratio of elements in a compound.
- Therefore; we need to get the ratio of moles of the above elements;
Aluminium : Sulfur : Oxygen
0.585 mol : 0.877 mol : 3.5075 mol
0.585/0.585 : 0.877/0.585 : 3.5075/0.585
1 : 1.5 : 6
But, we need whole number ratios, therefore;
= (1 : 1.5 : 6 ) × 2
= 2 : 3 : 12
Therefore; the formula of the compound is Al₂S₃O₁₂
The compound is written as Al₂(SO₄)₃
Thus, the empirical formula of the compound is Al₂(SO₄)₃
