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Ne4ueva [31]
4 years ago
9

If an element has two isotopes, what is the atomic mass if one of the isotopes has a mass of 15.000 amu and makes up 5.000% of t

he mass of the element while the other isotope has a mass of 16.000 amu and make up the remaining 95.000 %?
Chemistry
1 answer:
olasank [31]4 years ago
8 0
The atomic mass of element is the weighted average atomic mass of the element with respect to the abundance of the isotopes of that element 
atomic mass is the sum of the products of the mass of isotopes by their percentage abundance 
atomic mass = 15.000 amu x 5.000 % + 16.000 amu x 95.000 % 
                     = 0.7500 + 15.200
atomic mass of element is therefore 15.950
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The stearic acid/hexane solution contains 0.1 g of stearic acid per 1 ml of solution. what is the molarity of this solution? g
melisa1 [442]
Stearic acid formula is CH₃(CH₂)₁₆COOH
The molecular mass of stearic acid is 284.48 g/mol
The mass of stearic acid in 1 ml of solution is 0.1 g
Therefore number of moles in 1 ml is - 0.1 g / 284.48 g/mol = 0.000352 mol
Molarity is number of moles in 1 L of solution
If 1 ml contains - 0.000352 mol
Then 1 L solution contains - 0.000352 /1 x 1000 = 0.352 mol/L
Therefore molarity is 0.352 M
8 0
3 years ago
Given the reaction below:
lidiya [134]

The given equation is  is

2Cu+8HNO_{3}-->3Cu(NO_{3})_{2}+2NO+4H_{2}O

this is not balanced

The balanced equation will be:

3Cu+8HNO_{3}-->3Cu(NO_{3})_{2}+2NO+4H_{2}O

Now as per it if we are using eight moles of HNO3 we are getting two moles of NO

so for each mole of NO we have to take four moles of HNO3

Hence the mole ratio of NO produced to HNO3 reacted will be = 1:4

4 0
3 years ago
2C4H10+13O2-->8CO2+10H2O Using the predicted and balanced equation, How many Liters of CO2 can be produced from 150 grams of
Anna11 [10]

Answer:  233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} C_4H_{10}=\frac{150g}{58g/mol}=2.59moles

The balanced chemical equation is:

2C_4H_{10}+13O_2(g)\rightarrow 8CO_2+10H_2O  

According to stoichiometry :

2 moles of C_4H_{10} produce =  8 moles of CO_2

Thus 2.59 moles of C_4H_{10} will produce=\frac{8}{2}\times 2.59=10.4moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=10.4moles\times 22.4mol/L=233L

Thus 233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

8 0
4 years ago
What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?
Karo-lina-s [1.5K]
x 0,025
HCl+KOH--> KCl + H2O
1 1


c=1M
V=25ml=0,025l ( you need the volume to be in l)
c = n/V
n=c*V
n=1*0,025=0,025 m KOH


x=0,025m
c=1 M
V=n/c
V=0,025/1=0,025l=25ml HCl
3 0
3 years ago
Helppppppppppppppppp
igor_vitrenko [27]

Answer:

0.028578 km

Explanation:

The following data were obtained from the question:

Length of whale (in mm) = 28578 mm

Length of whale (in km) =?

We can convert 28578 mm to km by doing the following:

Recall:

1 mm = 1×10¯⁶ Km

Therefore,

28578 mm = 28578 mm × 1×10¯⁶ Km / 1 mm

28578 mm = 0.028578 km

Thus, 28578 mm is equivalent to 0.028578 km

The length of whale (in km) = 0.028578 km

3 0
4 years ago
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