Answer:
It's a parabola.
Step-by-step explanation:
we have

we know that
<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.
So
in this problem
the constant term is equal to 
and the first monomial is equal to
-----> coefficient is 
So
possible values of p are 
possible values of q are 
therefore
<u>the answer is</u>
The all potential rational roots of f(x) are
(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
Answer:A terminating decimal between -3.14 and -3.15.
Step-by-step explanation:
A natural number includes non-negative numbers like 5, 203, and 18476.
It is encapsulated by integers, which include negative numbers like -29, -4, and -198.
Integers are further encapsulated by rational numbers, which includes terminating decimals like 3.14, 1.495, and 9.47283.
By showing a terminating decimal between -3.14 and -3.15, you are showing that rational numbers include integers (because integers include negative numbers.
Answer:
Step-by-step explanation:
y =4/3 x+4
slope intercept form
y = mx+b
the y intercept is 4 (0,4)
and the slope is 4/3 which is change in y over change in x
we go up 4 to the right 3
we can rewrite the slope as -4/-3
so we can go down 4 and to the left 3
this would be point (-3,0)
we have 2 points marked, now draw a line throught them