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3 years ago

How old am I if 300 reduced by 3 times my age is 102

Mathematics

2 answers:

Lilit [14]3 years ago

4 0

Answer:

x = age

200 - 3x = 47, solve for x

x =51

Step-by-step explanation:

Yuri [45]3 years ago

3 0

Answer:

Step-by-step explanation:

= 300 - 3x = 102

= 300 = 3x + 102

= 300 = 3x

-102

= 198 = 3x

= 198 / 3 = x

= 66 = x

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Find the center and radius of circle and graph it <br><br> <img src="https://tex.z-dn.net/?f=%28x-4%29%5E%7B2%7D%20%2B%28%20y%20

sergeinik [125]

Answer:

centre = (4,-2)

radius = 3

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

So, by translating we can say that

centre = (4,-2)

and

radius = 3

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3 years ago

harry invests £6000 in a savings account. the account pays 3.4% compound interest per year. work out the value of his investment

Nataly_w [17]

Invested amount (P0 = £6000.

Rate of interest (r) = 3.4% = 0.034.

We know compound interest formula

A = P(1+r)^t

We need work out the value of his investment per year.

So, we need to plug t=1 and plugging values of P and r in the formula above, we get

A = 6000(1+0.034)^1

A = 6000(1.034)

A = 6204.

<h3>Therefore, the value of his investment per year is £ 6204.</h3>

Now, we need to work out the value of his investment after 3 years.

So, we need to plug t=3.

A = 6000(1+0.034)^3

A = 6000(1.034)^3

1.034^3=1.105507304

A = 6000 × 1.105507304

A = 6633.04

<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>

6 0

3 years ago

Assume that there are 365 days in a year, the probability that a person is born on any given day is the same for all days, and e

Artemon [7]

Answer:

Step-by-step explanation:

If each day equal chance then p = Prob that a person is borne on a particular day = 1/365

Each person is independent of the other and there are two outcomes either borne in July or not

p = prob for one person not borne in July = (365-31)/365 = 334/365

a)Hence prob that no one from n people borne in July = $(\frac{334}{365} )^n$

b) p = prob of any one borne in July or Aug = $\frac{(31+31) }{365} =\frac{62}{365}$ =0.1698

X- no of people borne in July or Aug

n =15

P(X>=2) = $15C2 (0.1698)^2*(1-0.1698)^{13} +15C3 (0.1698)^3*(1-0.1698)^{12} +...+15C15 (0.1698)^{15}$

=0.7505

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3 years ago

1. Contaminated water is subjected to a cleaning process. The concentration of the

Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

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3 years ago

Please help me fill this in

Rom4ik [11]

Answer:

380.13m squared

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3 years ago