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olganol [36]
4 years ago
9

How much water, in grams, can be made from 1.03 x

4}" alt="10^{24}" align="absmiddle" class="latex-formula"> hydrogen molecules? Answer in units of g.
Chemistry
1 answer:
krok68 [10]4 years ago
5 0

Answer:

30.8 g of water are produced

Explanation:

First of all we need the equation for the production of water:

2H₂ + O₂ → 2H₂O

2 moles of hydrogen react with 1 mol of oxygen in order to produce 2 moles of water.

As we assume, the oxygen in excess, we determine the moles of H₂.

1.03ₓ10²⁴ molecules . 1 mol/ 6.02ₓ10²³ molecules = 1.71 moles

Ratio is 2:2, so 1.71 moles will produce 1.71 moles of water

Let's convert the moles to mass: 1.71 mol . 18g / 1mol = 30.8 g of water are produced

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Refer to the graph. the graph shows the progress of digestion as carbohydrates, fats, and proteins pass through the human digest
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Name the bonds found between amino acids in a polypeptide chain
Mekhanik [1.2K]

Answer:

<em><u>Primary Structure: Amino Acids Are Linked by Peptide Bonds to Form Polypeptide Chains. Proteins are linear polymers formed by linking the α-carboxyl group of one amino acid to the α-amino group of another amino acid with a peptide bond (also called an amide bond).</u></em>

Explanation:

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8 0
3 years ago
Read the chemical equation. Fe2O3 + CO → Fe + CO2 If 2 moles of Fe2O3 react with 9 moles of CO, how many moles of each product a
cluponka [151]

Answer:

4 moles Fe and 6 moles CO2 are the moles of each products formed

Explanation:

Fe2O3 + 3CO → 2Fe + 3CO2

1st step Ballance the equation. Afterwards, you can work properly

1 mol of Fe2O3 reacts with 3 moles of CO to make 2 moles of Fe and 3 moles of CO2

2nd step Predict the reactant in excess and limitant reagent.

If 1 moles of Fe2O3 reacts with 3 moles of CO

2 moles of Fe2O3 reacts with 6 moles of CO     (2.3) /1

I have 9 moles of CO, so the Fe2O3 is my limitant reagent.

<u><em>REMEMBER</em></u> you always have to work with the limitant.

If 3 moles of CO reacts with 1 mol of Fe2O3

9 moles of CO reacts with 3 moles of Fe2O3     (9.1) /3

I have 2 moles of Fe2O3, so I still have Fe2O3, by the way the CO is the reactant in excess. (Just to show all)

3rd step Work with the limitant reagent.

1 mol of Fe2O3 ___ makes____ 2 moles of Fe  +  3 moles of CO

2 mol of Fe2O3 ___ makes ___ 4 moles of Fe  +  6 moles of CO

5 0
3 years ago
an element "x" has the election configuration 2,8,3 this element is found in ______group and_____period A.3,llla B.llla,3 C.vlla
iogann1982 [59]

This element is found in group 3A, period 3

<h3>Further explanation </h3>

The maximum number of electrons that can be filled in the nth electron shell is 2n²(n=shell)

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  • L shell (n = 2) maximum 2 x 2² = 8 electrons
  • M shell (n = 3) maximum 2 x 3² = 18 electrons
  • N shell (n = 4) maximum 2 x 4² = 32 electrons

Electron configuration of element X : 2.8.3 , so :

K shell = 2 ⇒1s²

L shell = 8⇒2s²2p⁶

M shell = 3⇒ 3s²3p¹

Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

The outer shell 3s²3p¹ : located in group 3A and period 3

group⇒valence electron ⇒3

period⇒the greatest value of the quantum number n⇒3

3 0
3 years ago
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