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Veronika [31]
2 years ago
5

Which of these is NOT a unit of pressure psi atm mm Torr

Chemistry
1 answer:
Alexxx [7]2 years ago
7 0
I think mm is not a unit of pressure
You might be interested in
Jaką maksymalną ilość gramów azotanu (V) potasu można rozpuscic w 300g wody w temperaturze 90 C
olga2289 [7]

Answer:

  • <u>609g </u>

<u></u>

Explanation:

The translated question is:

<em>What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C</em>

<em></em>

<h2>Solution</h2>

<em></em>

To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.

The attached table contains the solutibility table for KNO₃ at different temperatures.

At 90ºC it is 203g / 100g water.

Then, to calculate the <em>maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C</em>, just multiply by the amount of water:

  • 203g / 100g water × 300 g water = 609g ← answer

6 0
3 years ago
What is the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm
Virty [35]

The volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.

<h3>How to calculate volume?</h3>

The volume of a given mass of gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • R = gas law constant
  • T = temperature
  • n = number of moles

According to this question, 0.98 moles of oxygen gas at 275 k contains a pressure of 2.0 atm. The volume is calculated as follows:

2 × V = 0.98 × 0.0821 × 275

2V = 22.13

V = 11.06L

Therefore, the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.

Learn more about volume at: brainly.com/question/12357202

#SPJ1

6 0
2 years ago
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205)
tiny-mole [99]

Answer:

204.73K

Explanation:

the formula : PV=nRT

n=4

P=5.6 atm

V=12 L

R=0.08206 L atm mol-1 K-1

T=?

So, if you plug it in, you will get:-

T=PV/nR

T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)

T=204.73 K

hope this is correct!

4 0
3 years ago
Why is fractional distillation not used to produce drinking water from sea water?
Natasha_Volkova [10]

Answer:

Please mark me brainliest. the answer is

Explanation:

The problem is that the desalination of water requires a lot of energy. Salt dissolves very easily in water, forming strong chemical bonds, and those bonds are difficult to break. Energy and the technology to desalinate water are both expensive, and this means that desalinating water can be pretty costly.

4 0
3 years ago
On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of
Murrr4er [49]

Answer:

The empirical formula of the organic compound is  = C_2H_6S_1

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of CO_2 gas at STP occupying 2.0 L = n

n\times 22.4L=2.0L

n=\frac{2.0 L}{22.4 L}=0.08929 mol

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of H_2O gas at STP occupying 3.0 L = n'

n'\times 22.4L=3.0L

n'=\frac{3.0 L}{22.4 L}=0.1339 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of SO_2 gas at STP occupying 1.0 L = n''

n''\times 22.4L=1.0L

n''=\frac{1.0 L}{22.4 L}=0.04464 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = \frac{0.08920 mol}{0.04464 mol}=2

Hydrogen =  \frac{0.2678 mol}{0.04464 mol}=6

Sulfur = \frac{0.04464 mol}{0.04464 mol}=1

The empirical formula of the organic compound is  = C_2H_6S_1

3 0
3 years ago
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