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3 years ago

-The picture goes to Activity 2

Chemistry

2 answers:

Alborosie3 years ago

4 0

Answer:

Activity 1: Since the only forces apposing the upward movement of the load are gravity and air resistance the formulas of which can both be solved with weight then with constant variables for gravity and air, effort IS directly proportional to weight.

Activity 2:

Inclined plane.

to make lifting easier; raising or lowering a load.

Explanation:

hope this helps.

sergey [27]3 years ago

3 0

Answer:

Ramp.

Explanation:

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Based on the location of nitrogen on the periodic table how many additional electrons does a nitrogen atom need in its valence s

igor_vitrenko [27]

1 additional electron

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3 years ago

Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the numbe

IceJOKER [234]

The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

<h3>Is BF3 molecule stable or not?</h3>

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

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1 year ago

Which of the following statements is true regarding soundwaves?

Alexeev081 [22]

Answer: Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.

Explanation: i think its C

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2 years ago

Why are complex carbohydrates, such as starches, considered long-term energy sources? A. The human body can break down complex c

PilotLPTM [1.2K]

Answer:

A. The human body can break down complex carbohydrates into sugar molecules that provide energy.

Explanation:

Strings of glucose, form complex carbohydrates such as starch and glycogen. Glycogen which is a stored form of glucose in humans is a source of long-term energy, and a complex carbohydrate because glycogen can be converted to glucose-1-phosphate which can enter the glycolytic cycle to generate Adenosine triphosphate which is a unit of energy.

This stored form of energy can be slowly broken down to release energy when needed by the body. During exercise, for instance, glycogen can slowly release ATP needed for energy.

8 0

2 years ago

A student in chemistry 150-02 weighed out 55.5 g of octane (C8H18) and allowed it to react with oxygen, O2. The products formed

Anni [7]

Answer:

Explanation:

Given data:

Mass of octane = 55.5 g

Balanced chemical equation = ?

Mass of oxygen required to react = ?

Mass of CO₂ for med = ?

Molecules of water produced = ?

Mass of octane required to produced 30.0 g of water = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

Mass of oxygen required to react = ?

Mass of octane = 55.0 g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with oxygen.

C₈H₁₈ : O₂

2 : 25

0.48 : 25/2×0.48 = 6 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Mass = 6 mol × 32 g/mol

Mass = 192 g

Given data:

Mass of carbon dioxide produced = ?

Mass of octane = 55g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with CO₂.

C₈H₁₈ : CO₂

2 : 16

0.48 : 16/2×0.48 = 3.84 mol

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 3.84 mol × 44 g/mol

Mass = 168.96 g

Given data:

Molecules of water produced = ?

Mass of octane = 55g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with H₂O.

C₈H₁₈ : H₂O

2 : 18

0.48 : 18/2×0.48 = 4.32 mol

Number of molecules of water:

1 mol = 6.022× 10²³ molecules

4.32 mol × 6.022× 10²³ molecules/ 1 mol

26 × 10²³ molecules

Given data:

Mass of octane required = ?

Mass of water produced = 30 g

Solution:

Number of moles of water.

Number of moles = mass/ molar mass

Number of moles = 30 g/ 18 gmol

Number of moles = 1.67 mol

Now we will compare the moles of water and octane from balance chemical equation:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

H₂O : C₈H₁₈

18 : 2

1.67 : 2/18×1.67 = 0.185 mol

Mass of octane:

Mass = number of moles ×molar mass

Mass = 0.185 × 114.23 g/mol

Mass = 21.13 g

5 0

3 years ago