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photoshop1234 [79]
3 years ago
14

Why were chlorofluorocarbons first developed?

Chemistry
1 answer:
Sergio [31]3 years ago
5 0
CFCs and their associated compounds were developed in the early 1900s as a non-toxic, non-flammable solution to other more dangerous products such as ammonia.
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How many electrons are in a atom of zicronium
MrRissso [65]

Answer:

There are 40 electrons in one atom of Zirconium.

Explanation:

Note: The word is not zicronium, it is Zirconium.

3 0
3 years ago
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John dalton proposed a theory that all matter is made up of individuals particles which cannot be divided. what were those parti
juin [17]
The particles are atoms, his theory is the atomic theory
3 0
3 years ago
__ Cu + ___ HNO₃ → ___ _Cu(NO₃)₂ + ___ NO₂ + ___ H₂O
ivolga24 [154]

Answer:

Cu + 4HNO3 --->   Cu(NO3)2 + 2NO2 + 2H2O.

Explanation:

Balancing:

Cu + 4HNO3 --->   Cu(NO3)2 + 2 NO2 + 2H2O.

3 0
3 years ago
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Methylene chloride (CH2Cl2) has fewer chlorine atoms than chloroform (CHCl3). Nevertheless, methylene chloride has a larger mole
Talja [164]

Answer:

Explanation has been given below.

Explanation:

  • Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
  • Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
  • First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
  • Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
  • Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
  • Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.
6 0
3 years ago
The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:
alisha [4.7K]

Answer:

b. potassium.  

Explanation:

Potassium-sparing diuretics and salt substitutes are diuretics that eliminate salt and water but save potassium. They act by inhibiting the conducting sodium channels in the collecting tubule, such as amiloride and triamterene, or by blocking aldosterone, such as spironolactone.

Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

4 0
3 years ago
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