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photoshop1234 [79]
4 years ago
14

Why were chlorofluorocarbons first developed?

Chemistry
1 answer:
Sergio [31]4 years ago
5 0
CFCs and their associated compounds were developed in the early 1900s as a non-toxic, non-flammable solution to other more dangerous products such as ammonia.
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If 81g of water is measured out, how many moles are in the sample? *
valkas [14]

Answer:

D

Explanation:

because moles = mass /mr

so 81/18(mr of H2O=2+16)

moles =4.5

hope this helps:)

7 0
3 years ago
Помогите срочно сделать по химии промежуточную отестацию за 8 класс
il63 [147K]

Answer:

This is site for English  speakers.  Этот сайт на английском, поэтому вопрос могут удалить

Explanation:

1. 2)

2. 3)

3. 4) Sr

4. 3)

5. 4)

6. 2)

7. 1)

8. 4)

9. 3)

10. 3)

11. SO3, H2SO4, Na2SO4

12.

A) оксид меди (II) 2) CuO

Б) хлорид меди(II) 4) CuCl2

В) сульфит меди (II) 3) CuSO 3

Г) гидроксид меди (II) 1) Cu(OH)2

13.

1. Fe+HCl= б) FeCl 2 +H 2

2.Fe+O2= в) Fe 3 O 4

3. Fe(OH) 3  = г)Fe 2 O 3 +H 2O

4. FeCl 2 +NaOH= а) Fe(OH) 2 +NaCl

14. 2Ca + O2 = 2CaO

CaO + H2O = Ca(OH)2

Ca(OH)2 + 2HCl = CaCl2 + 2H2O

6 0
3 years ago
A 1.0 g sample of hydrogen reacts completely with 19.0 g of fluorine to form a compound of hydrogen and fluorine. a. What is the
Rashid [163]

Explanation:tr

a) Molar mass of HF = 20 g/mol

Atomic mass of hydrogen = 1 g/mol

Atomic mass of fluorine = 19 g/mol

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{Molar mass of compound }}\times 100

Percentage of fluorine:

\frac{1\times 19 g/mol}{20g/mol}\times 100=95\%

Percentage of hydrogen:

\frac{1\times 1g/mol}{20 g/mol}\times 100=5\%

b) Mass of hydrogen in 50 grams of HF sample.

Moles of HF = \frac{50 g}{20 g/mol}=2.5 mol

1 mole of HF has 1 mole of hydrogen atom.

Then 2.5 moles of HF will have:

1\times 2.5 mol=2.5 mol of hydrogen atom.

Mass of 2.5 moles of hydrogen atom:

1 g/mol × 2.5 mol = 2.5 g

2.5 grams of hydrogen would be present in a 50 g sample of this compound.

c) As we solved in part (a) that HF molecules has 5% of hydrogen by mass.

Then mass of hydrogen in 50 grams of HF compound we will have :

5% of 50 grams of HF = \frac{5}{100}\times 50 g=2.5 g

8 0
3 years ago
What are the reactants and products? Write a reaction equation and label the reactants and products.
djyliett [7]
Reactants are the substance that undergo a change in a chemical reaction while products are what is produced after a reaction. don't have time to write a reaction.
8 0
3 years ago
Read 2 more answers
What is the reason for the low solubility of LiF (0.27 g
Brut [27]

Answer:

The answer is C. The high solvation energy for LI+

Explanation:

LiF has lower solubility because of the high solvation energy of Li+ ion. This is due to the smaller  size and very big charge compared to Cs+ ion which has a bigger size and solvent molecules easily surround it.

Solvation energy is simply the amount energy that is required to make a solute dissolve in a solvent.

3 0
3 years ago
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