The question is incomplete. The complete question is :
A plate of uniform areal density
is bounded by the four curves:




where x and y are in meters. Point
has coordinates
and
. What is the moment of inertia
of the plate about the point
?
Solution :
Given :




and
,
,
.
So,

, 



![$I=2 \int_1^2 \left( \left[ (x-1)^2y+\frac{(y+2)^3}{3}\right]_{-x^2+4x-5}^{x^2+4x+6}\right) \ dx$](https://tex.z-dn.net/?f=%24I%3D2%20%5Cint_1%5E2%20%5Cleft%28%20%5Cleft%5B%20%28x-1%29%5E2y%2B%5Cfrac%7B%28y%2B2%29%5E3%7D%7B3%7D%5Cright%5D_%7B-x%5E2%2B4x-5%7D%5E%7Bx%5E2%2B4x%2B6%7D%5Cright%29%20%5C%20dx%24)



So the moment of inertia is
.
Answer:
0.8726 
Explanation:
We are to convert 1.85 x
to 
First, let us convert the numerator from ft3 to m3
1 ft3 = 0.0283 m3
Hence,
1.85 x
ft3 = 1.85 x
x 0.0283 m3
= 52.355 m3
Now, let us convert the denominator from minutes to seconds
1 min = 60 sec
Therefore;
1.85 x
= 52.355/60 
= 0.8726 
The harmonic frequency of a musical instrument is the minimum frequency at which a string that is fixed at both ends in the instrument may vibrate. The harmonic frequency is known as the first harmonic. Each subsequent harmonic has a frequency equal to:
n*f, where n is the number of the harmonic and f is the harmonic frequency. Therefore, the harmonic frequency may be calculated using:
f = 100 / 2
f = 50 Hz
<span>This
is because astronomers have discovered that
the Crab Nebula is 6500 light years from earth. This means it takes 6500 earth years
for light to get from the Crab Nebula to
earth. Therefore, if we are able to observe the
Crab Nebula and beyond it then it means that earth has been in existence for 6500 years and
over. </span>