Given: Work W = 44 J; Mass of the rope and the bucket m= 1.5 Kg
Required: Find the height in meters
Formula: Work = Force x distance but Force = Weight = mg g = 9.8 m/s²
W =Fd W = mgh h = W/mg
h = 44 J/(1.5 Kg)(9.8 m/s²)
h = 2.99 m or 3 m
Solving for the two unknowns using systems of linear equations (substitution or elimination method):
m= 11.9; b=-23.5
y=11.9x - 23.5
y=11.9*4-23.5
y=24.1
Therefore when x=4, the approximate value of y is 24.1
Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
When is at the end of the runway the velocity of the plane is given by the equation
where s=1800 m is the runway length. Thus
At half runway the velocity of the plane is
Therefore at midpoint of runway the percentage of takeoff velocity is
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Answer:
All planets have an elliptical orbit
all planets have roughly the same SHAPE of orbit