To determine the distance that you would travel by.
Simply convert 15 minutes to seconds which would be 900 seconds.
Then solve for distance, which would be
D = r • t
D = 12 m/s • 900 s
D =10 800 m.
This is the distance that you had ran for.
Answer:
Thus simply tells us that The nut has no net charge and so therefore, There will be a negative charge on the left side, and an equal positive charge on the right side
Answer:
R = 103.7 N, 31.6° above x-axis
Explanation:
First we find the x components of all the forces:
F1x = F1 Cos 60°
F1x = (100 N)(Cos 60°)
F1x = 50 N
F2x = F2 Cos 140°
F2x = (200 N)(Cos 140°)
F2x = -153.2 N
F3x = F3 Cos 320°
F3x = (250 N)(Cos 320°)
F3x = 191.5 N
So, the x component of resultant will be the sum of the x component of each force:
Rx = F1x + F2x + F3x
Rx = 50 N - 153.2 N + 191.5 N
Rx = 88.3 N
Now we find the y components of all the forces:
F1y = F1 Sin 60°
F1y = (100 N)(Sin 60°)
F1y = 86.6 N
F2y = F2 Sin 140°
F2y = (200 N)(Sin 140°)
F2y = 128.5 N
F3y = F3 Sin 320°
F3y = (250 N)(Sin 320°)
F3y = -160.7 N
So, the y component of resultant will be the sum of the y component of each force:
Ry = F1y + F2y + F3y
Ry = 86.6 N + 128.5 N - 160.7 N
Ry = 54.4 N
Hence, the magnitude of resultant force will be:
|R| = √(Rx² + Ry²)
|R| = √[(88.3 N)² + (54.4 N)²]
|R| = √10756.25 N²
|R| = 103.7 N
And the direction θ will be:
θ = tan⁻¹(Ry/Rx)
θ = tan⁻¹(54.4/88.3)
θ = 31.6° above x-axis
Hence, the resultant vector will be:
<u>R = 103.7 N, 31.6° above x-axis</u>
They will mix with air. Air consists mostly of nitrogen and oxygen but there are also traces of CO2 and noble gases in air, and helium is one of those noble gases.
Answer:
12.245m3
Explanation:
The electric energy is created by The potential energy substended by the specific volume of water in dam.
Electric energy is calculated as
E= Q× V
E is Energy, Q is charge and V is Voltage
Note that this energy has been given and is 60Joules
From conservation of energy it means;
M× g×h = 60
Where M is the mass of water.
g is acceleration of free fall due to gravity which is 9.8m/S2
h is the height of water flow.
From change of subject of formula for M; we have:
M = 60/ g × h
= 60/ 9.8 × 0.5
= 12.245kg
Now how much water required means the volume of water;
Note density = mass/volume
Therefore volume = mass/density
=12.245/1= 12.245m3
Note the density of water is 1kg/m3