Can someone help me plz!!!

LEARNING ACTIVITY SHEET

Nady [450]

Answer:

1. It is used to test/check the continuity of the circuit

a. Ohmmeter

2. Is a physical device used to connect electronic test equipment to a device under test

a. Test probes

3. A device inserted to a convenience outlet to conduct electric current

a. Plug

4. Is a stranded wire used to temporary wiring installation and commonly used in extension cord assembly

a. Duplex cord

5. It is a pocket size tool used to test the line wire or circuit if there is a current in it.

a. Test light

6. An instrument used to measure the amount of electrical current intensity in a circuit

b. Ammeter

7. A pocket sized tool used to test the line wire or circuit if there is current in it.

a. Test light

8. A measuring tool used to measure the length of an object in centimeter in it

b) Ruler

9. It is used to measure the diameter of wires/conductors in circular mills. It can measure small and big sizes of wires

a. Micrometer

10. It is used to measure the voltage, resistance and current of a circuit. It is connected in parallel or series with the circuit depending on what to measure

a) Volt-Ohm-milliammeter

11. It is the measuring tool used to measure length, width and thickness of short object and in sketching straight line

Foot rule/ ruler

Explanation:

1. An Ohmmeter tests resistance of a circuit and therefore, indicates if the circuit has continuity (connectivity) by measuring the resistance to the current it sends through the circuit, while the circuit power is switched off

2. A test probe connects a testing equipment to a Device Under Test (DUT)

3. A plug is used to connect an electric appliance to the mains power supply by fitting it into the mains power outlet

4. A duplex cord is used for temporary wiring to supply power in an extension cord assembly

5. A test light is used to determine if a circuit has electric current flowing in it

6. An ammeter measures the amount of direct or alternating current flowing in a circuit

7. Test light is used to check the presence of an electric current in a circuit

8. A ruler is used to measure length and it is marked in cm or in

9. A micrometer measures the diameter of wires placed in between the anvil and spindle

10. A Volt-Ohm-Milliammeter (VOM), is also known as a multimeter that measures voltage, current, and resistance of a circuit

11. A foot rule/ ruler, measures the dimensions of objects that are flat and short

3 0

3 years ago

If aligned and continuous carbon fibers with a diameter of 9.90 micron are embedded within an epoxy, such that the bond strength

Zielflug [23.3K]

I have no idea what it is

8 0

3 years ago

A solid shaft and a hollow shaft of the same material have same length and outer radius R. The inner radius of the hollow shaft

alexandr402 [8]

Answer with Explanation:

By the equation or Torque we have

$\frac{T}{I_{p}}=\frac{\tau }{r}=\frac{G\theta }{L}$

where

T is the torque applied on the shaft

$I_{p}$ is the polar moment of inertia of the shaft

$\tau$ is the shear stress developed at a distance 'r' from the center of the shaft

$\theta$ is the angle of twist of the shaft

'G' is the modulus of rigidity of the shaft

We know that for solid shaft $I_{p}=\frac{\pi R^4}{2}$

For a hollow shaft $I_{p}=\frac{\pi (R_o^4-R_i^4)}{2}$

Since the two shafts are subjected to same torque from the relation of Torque we have

1) For solid shaft

$\frac{2T}{\pi R^4}\times r=\tau _{solid}$

2) For hollow shaft we have

$\tau _{hollow}=\frac{2T}{\pi (R^4-0.7R^4)}\times r=\frac{2T}{\pi 0.76R^4}$

Comparing the above 2 relations we see

$\frac{\tau _{solid}}{\tau _{hollow}}=0.76$

Similarly for angle of twist we can see

$\frac{\theta _{solid}}{\theta _{hollow}}=\frac{\frac{LT}{I_{solid}}}{\frac{LT}{I_{hollow}}}=\frac{I_{hollow}}{I_{solid}}=1.316$

Part b)

Strength of solid shaft = $\tau _{max}=\frac{T\times R}{I_{solid}}$

Weight of solid shaft = $\rho \times \pi R^2\times L$

Strength per unit weight of solid shaft = $\frac{\tau _{max}}{W}=\frac{T\times R}{I_{solid}}\times \frac{1}{\rho \times \pi R^2\times L}=\frac{2T}{\rho \pi ^2R^5L}$

Strength of hollow shaft = $\tau '_{max}=\frac{T\times R}{I_{hollow}}$

Weight of hollow shaft = $\rho \times \pi (R^2-0.7R^2)\times L$

Strength per unit weight of hollow shaft = $\frac{\tau _{max}}{W}=\frac{T\times R}{I_{hollow}}\times \frac{1}{\rho \times \pi (R^2-0.7^2)\times L}=\frac{5.16T}{\rho \pi ^2R^5L}$