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3 years ago

6

Tom wanted to buy a hunting dog with a waterproof undercoat and a good sense of smell. Which type of genetic engineering would h

elp Tom find the right dog?
a. GMO
b. biomedical research
C. Selective breeding
D. Mutation research

1 answer:

skad [1K]3 years ago

8 0

B. Biomedical Research

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zmey [24]

11.54 minutes

Explanation:

The decay rate equation is given by

$N = N_0e^{-\frac{t}{\lambda}}$

where $\lambda$ is the half-life. We can rewrite this as

$\dfrac{N}{N_0} = e^{-\frac{t}{\lambda}}$

Taking the natural logarithm of both sides, we get

$\ln \left(\dfrac{N}{N_0}\right) = -\left(\dfrac{t}{\lambda}\right)$

Solving for $\lambda$ ,

$\lambda = -\dfrac{t}{\ln \left(\frac{N}{N_0}\right)}$

$\:\:\:\:= -\dfrac{(24\:\text{minutes})}{\ln \left(\frac{1000\:\text{counts/min}}{8000\:\text{counts/min}}\right)}$

$\:\:\:\:=11.54\:\text{minutes}$

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A 80.0kg football player running at 12.5 m/s North runs into a 120.kg player running South. The 120.kg player grabs the other on

Masteriza [31]

Answer:

p=-540kg•m/s

Explanation:

because I used a calc

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4 years ago

A person uses a waterproof computer to generate a simple musical tone underwater. It takes 8 s for the tone to travel 3,000 m. I

Svetach [21]

Answer:

$\lambda=0.5m$

Explanation:

Wavelength is the distance between two successive crests of a wave or the <em>distance</em> it takes before the wave's shape repeats itself.

It's given as the velocity of the wave divided by it's frequency.

$\lambda$ -Distance between any two wave crests.

$v$ -velocity, speed at it the wave is moving in a given direction.

$f$ -frequency, number of waves going through a certain point in a acertain time. Measured in cycles/sec or Hz

f=750Hz

$\lambda=\frac{v}{f}\\v=\frac{3000}{8}=375m/s\\\lambda=\frac{375m/s}{750Hz}\\\lambda=0.5m$

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3 years ago

“All dogs bark. Fido barks. Thus, Fido is a dog,” is an example of which of the following?

nalin [4]

Deductive reasoning?

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3 years ago

g While hauling a log in the back of a flatbed truck, a driver is pulled over by the state police. Although the log cannot roll

irga5000 [103]

Answer:

The minimum coefficient of static friction required, µ = 0.10

<em>Note. The question is incomplete. The complete question is given below:</em>

<em>While hauling a log in the back of a flatbed truck, a driver is pulled over by the state police. Although the log cannot roll sideways, the police claim that the log could have slid out the back of the truck when accelerating from rest. The driver claims that the truck could not possibly accelerate at the level needed to achieve such an effect. Regardless, the police write a ticket anyway and now the driver court date is approaching.</em>

<em>The log has a mass of m = 929 kg; the truck has a mass of M = 8850 kg. According to the truck manufacturer, the truck can accelerate from 0 to 55 mph in 23.0 seconds, but this does not account for the additional mass of the log. Calculate the minimum coefficient of static friction μs needed to keep the log in the back of the truck.</em>

Explanation:

First, velocity in mph is converted to m/s

1 mph = 0.447 m/s

55 mph ≈ 24.6 m/s

The acceleration of the empty truck is a = v/t = 24.6 / 23 = 1.07 m/s²

Force that can be generated by the truck, F = ma

F = 8850kg * 1.07 m/s² = 9469.5 N

However, with the added mass of the log on it, the acceleration of the truck will become;

a = F / m = 9469.5 N / (8550+929)kg = 0.97 m/s²

Frictional force between the log and the truck = 0.97 m/s² * 929 kg = 901.13 N

Normal reaction on the truck due to the weight of the log, R = mg

R = 929 kg * 9.8m/s² = 9104.2 N

Coefficient of static friction, µ = F/R

µ = 901.13/9104.2

µ = 0.098 ≈ 0.10

Therefore, the minimum static friction required is µ = 0.10

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3 years ago