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aleksklad [387]
3 years ago
14

Temperature definition

Chemistry
2 answers:
laila [671]3 years ago
7 0

Answer:

degree of hotness or coldness measured on a definite scale.  the degree of heat that is natural to the body of a living being. abnormally high body heat running a temperature.

Explanation:

melamori03 [73]3 years ago
4 0

Answer:

degree of hotness or coldness measured on a definite scale.

Explanation:

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True or False: Different substances, like shortening and soap, will melt at the same temperature. True False​
stiks02 [169]
Answer: true

explanation:
8 0
3 years ago
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The reaction, 2C4H10 (g) + 13O2 (g) à 8CO2 (g) + 5H2O (g), is the combustion of butane. What occurs as the reaction proceeds?
Solnce55 [7]
The reaction, 2 C4H10 (g) + 13 O2 (g) = 8 CO2 (g) + 5 H2O (g), is the combustion of butane.   A combustion reaction involves the reaction of a hydrocarbon with oxygen producing carbon dioxide and water. This reaction is exothermic which means it releases energy in the form of heat. Therefore, as the reaction proceeds,a heat energy is being given off by the reaction. This happens because the total kinetic energy of the reactants is greater than the total kinetic energy of the products. So, the excess energy should be given off somewhere which in this case is released as heat.
7 0
4 years ago
Treatment of 2,4,6-tri-tert-butylphenol with bromine in cold acetic acid gives the compound C18H29BrO in quantitative yield. The
Cloud [144]

Answer:

2,4,6-tri-tert-butylcyclohexa-2,5-dienone

Explanation:

1. Information from the formulas

C₁₈H₃₀O ⟶ C₁₈H₂₉BrO

A Br has replaced an H.

2. Information from the reaction

These look like the conditions for an electrophilic aromatic substitution.

3. Possible mechanism (Fig. 1)

The product must be highly symmetrical, because there are so few NMR signals.

(i) The bromonium ion attacks at the para position, forming a resonance-stabilized carbocation intermediate.

(ii) A bromide ion attacks the H of the hydroxyl group to form 2,4,6-tri-tert-butylcyclohexa-2,5-dienone.

4. Confirmatory evidence (Fig. 2)

(a) Infrared  

1630 cm⁻¹:  C=O stretch

1655 cm⁻¹ : C=C stretch

(b)NMR

1.2 (9h, s):    the 4-tert-butyl group

1.3 (18H, s): the 2- and 6- tert- butyl groups

6.9 (2H, s):    the alkene H atoms

The ratio is 9:18:2.

3 0
3 years ago
How is structure linked to function? <br><br><br><br><br> please no upload files.
Gemiola [76]

Answer:In biology, a key idea is that structure determines function. In other words, the way something is arranged enables it to play its role, fulfill its job, within an organism. Structure-function relationships arise through the process of natural selection.

4 0
4 years ago
Oxygen forms a number of compounds with nitrogen, many of which are quite reactive. One such compound is 36.86 % by mass N . Cal
Delicious77 [7]

Answer:

75.37 g

Explanation:

From the question given above, the following data were obtained:

Percentage of nitrogen (N) in the compound = 36.86 %

Mass of nitrogen (N) in the compound = 44 g

Mass of oxygen (O) in the compound =?

Next, we shall determine the total mass of the compound. This can be obtained as follow:

Percentage of nitrogen (N) in the compound = 36.86 %

Mass of nitrogen (N) in the compound = 44 g

Total mass of compound (T) =?

Percentage of N = mass of N/ total mass × 100

36.86 % = 44 / T

36.86 / 100 = 44 / T

Cross multiply

36.86 × T = 100 × 44

36.86 × T = 4400

Divide both side by 36.86

T = 4400 / 36.86

Total mass = 119.37 g

Next, we shall determine the percentage of oxygen in the compound. This can be obtained as follow:

Percentage of N = 36.86 %

Percentage of O =?

Percentage of O = 100 – 36.86 %

Percentage of O = 63.14 %

Finally, we shall determine the mass of oxygen in the compound. This can be obtained as follow:

Percentage of O = 63.14 %

Total mass = 119.37 g

Mass of O =.?

Percentage of O = mass of O / total mass × 100

63.14 % = Mass of O / 119.37

Cross multiply

Mass of O = 63.14 % × 119.37

Mass of O = (63.14 / 100)× 119.37

Mass of O = 75.37 g

Thus, the mass of oxygen in the compound is 75.37 g

7 0
3 years ago
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