<span>1.44x10^23 molecules of oxygen gas
The ideal gas law is
PV = nRT
where
P = pressure (800.0 Torr)
V = volume (5.60 L)
n = number of moles
R = Ideal gas constant (62.363577 L*Torr/(K*mol) )
T = absolute temperature (27C + 273.15 = 300.15 K)
Let's solve for n, the substitute the known values and solve.
PV = nRT
PV/RT = n
(800.0 Torr*5.60 L)/(62.363577 L*Torr/(K*mol)*300.15 K) = n
(4480 L*Torr)/(18718.42764 L*Torr/mol) = n
0.239336342 mol = n
So we have 0.239336342 moles of oxygen molecules. To get the number of atoms, we need to multiply by avogadro's number, so:
0.239336342 * 6.0221409x10^23 = 1.44x10^23</span>
I think it's the Terminals
Answer:
The intermediates in this reaction are Cl and CCl₃.
Explanation:
- To indicate the intermediate in this reaction, we should firstly define the intermediate.
- The intermediate is the species that produced within the steps of the reaction and consumed in the later step/s and does not appear in the overall reaction (<em>neither reactants nor products</em>).
- The mechanism of the reaction contains 3 steps:
- Cl₂ ↔ 2Cl
- Cl + CHCl₃ → HCl + CCl₃
- Cl + CCl₃ → CCl₄
- The overall reaction is: Cl₂ + CHCl₃ → HCl + CCl₄
- So, the intermediates in this reaction are Cl and CCl₃.
- Thus, 2 moles of Cl is produced in the first step and consumed in the second and third steps.
- 1 mole of CCl₃ is produced in the second step and consumed in the third step.
