Answer: Andre. If it is used as an antifreeze, one would infer that it's freezing point is less than water.
Explanation:
The freezing point of ethylene glycol alone (100%) is -12.9oC. That is somewhat less than the freezing point of water but nowhere near the freezing point of water containing 70% ethylene glycol.
The molarity of the base ( ammonium hydroxide) is calculated as follows
find the moles of Nitric acid =molarity x volume
=29.5 x 0.175 =5.163 moles of nitric acid
write the equation for reaction
HNO3+ NH4OH =NH4NO3 +H2O
by use of mole ratio between HNO3 to NH4NO3 which is 1:1 the moles of NH4OH is also 5.163 moles
molarity =moles/volume
= 5.163 /50=0.103 M is the molarity of the base
Answer:
The substance is most likely NaCl.
Explanation:
Solubility:
As stated in statement the substance is insoluble in CCl₄ (Tetrachloromethane), it shows that the substance is polar in nature. In given options only C₁₀H₈ is soluble in CCl₄ because both are non polar in nature and like dissolves like. Hence, C₁₀H₈ is rejected.
Density:
Now, we are left with three options. NaCl, FeCl₃ and SiO₂. The student found that the density of substance is 2.20 g.mL⁻¹. Which is very close to the density of NaCl (i.e. 2.165 g.mL⁻¹). Therefore, most probably the substance the student is dealing with is Sodium Chloride.
Answer:
Well in one glucose they are 6.022*1023 individual glucose molecule.
Answer:
- 8.5gNaI × 1molNaI/78gNaI × 234.7g AgI / 1 MOL AgI × 2Mol Ag I / 1mol Na2S=51.2 g of AgI reacts with Na2 S
Explanation:
conversion factor is used to make sure that all the units cancels with the other units and we only remain with the mass of Ag I which is 51.2g but since the number of moles can be calculated by dividing with the relative molecular mass therefore 51.2g/234.7gmol=0.22mol
