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WINSTONCH [101]
3 years ago
9

At S?fndnfnfnfxmckfkffkfkfk ckfkfkfkfkfkv kfflfmcmc

Chemistry
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

what?

Explanation:

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How many moles of NH3 can be produced from 30.0 mol of H2 and excess N2?
VMariaS [17]
20 mol of NH, can be produce from 30 mol o H2
6 0
3 years ago
Salts are which part of an aqueous solution?
masha68 [24]

Explanation:

Salts are the solutes in an aqueous solution. An aqueous solution is solution whose solvent water.

  • To form a solution,a solute must be dissolved in a solvent.
  • For aqueous solutions, the solvent which is the dissolving medium is made up of water.
  • The solute is the substance that is dissolved in it.
  • Salts for example can be a solute in an aqueous solution.
  • A salt is generally an ionic compound consisting of positive ions such as metallic, ammonium ans complex ions and negative ions such as acid radicals and complex ions.

Learn more:

Aqueous solution brainly.com/question/8426727

#learnwithBrainly

3 0
3 years ago
If a young girl learned that it would be 0° C, or 32° F, the next
Ad libitum [116K]

Answer:

Cold

Explanation:

Because 0°C And below or 32°F Refers To Cold Weather

7 0
3 years ago
Ulfur dioxide gas can react in the presence of oxygen and vanadium(V) oxide to form sulfur trioxide. Sulfur trioxide is the only
LenaWriter [7]

According to the illustration, the vanadium (V) oxide would be a catalyst.

<h3>What are catalysts?</h3>

Catalysts are substances that are utilized in reactions that are not themselves consumed in reactions but only speed up the rate of the reactions.

Catalysts speed up the rate of reactions by lowering the activation energy of the reactants.

Sulfur dioxide reacts with oxygen to produce sulfur trioxide. The vanadium (v) oxide is not consumed in the reaction. Thus it only serves as a catalyst.

More on catalysts can be found here: brainly.com/question/12260131

#SPJ1

4 0
2 years ago
A student makes a mistake while preparing a vitamin C sample for titration and adds the potassium iodide solution twice. How wil
LiRa [457]

The added KI does not have any impact  

The reaction invovles Titration of vitaminc ( Ascorbic acid)

ascorbic acid + I₂ → 2 I⁻  +  dehydroascorbic acid

the excess iodine is free reacts with the starch  indicator, forming the blue-black starch-iodine complex.  

This is the endpoint of the titration. since alreay excess KI is added ( the source of Iodine), it does not have an influence.

Answer B

Hope this helps!

5 0
4 years ago
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