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Gnoma [55]
3 years ago
15

9. Elements that are characterized by the filling of p orbitals are classified as

Chemistry
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

p block elements

Explanation:

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there are 125 lima beans 56 garbanzo beans 39 kidney beans and 144 green peas in a container. find the percent by number of gree
Sauron [17]
39.6% of the beans are green beans
5 0
3 years ago
A sample of an unknown gas with a mass of 8.21 g has a volume of 4.8064 L when the temperature is 200oC and the pressure is 1.81
Pie

Answer:

The answer to your question is M = 36.49 g

Explanation:

Data

mass = 8.21 g

volume = 4.8064 L

Temperature = 200°C

Pressure = 1.816 atm

M = ?

Process

1.- Convert temperature to °K

°K = 273 + 200

°K = 473

2.- Calculate the number of moles

n = (PV)/RT

n = (1.816)(4.8064)/(0.082)(473)

n = 0.225

3.- Calculate the molar mass

            M --------------- 1 mol

           8.21 g ---------- 0.225 moles

M = (1 x 8.21)/0.225

M = 36.49 g

4 0
3 years ago
would you expect potassium to have a high electronegativity or a low electronegativity? explain your answer
GalinKa [24]

A low electronegativity

Explanation:

Potassium is a metal that is expected to have a very low electronegativity value.

Electronegativity is the relative tendency by which an atom attracts valence electrons in a chemical bond.

Potassium is an element in the first group on the periodic table.

The common trend is that electronegativity increases from left to right and decreases down a group.

  • Potassium as metal will prefer to lose electrons rather than attracting because that will make it achieve the octet configuration that will ensure its stability.
  • This is why it will have low electronegativity.

Learn more:

Electronegativity brainly.com/question/11932624

#learnwithBrainly

4 0
3 years ago
What is the hybridization of the central atom in becl2?
Anuta_ua [19.1K]
Its hybridization would be sp because Be only has 2 covalent bonds with Cl
4 0
3 years ago
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
Diano4ka-milaya [45]
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
3 years ago
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