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antiseptic1488 [7]
3 years ago
8

Dominick and eva are using the same type of stopwatches to measure the time it takes for a chemical reaction to occur. They can

use the same stopwatch to measure the time.
Chemistry
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

They did not repeat their tests multiple times.

Explanation:

It may seem that the question is incomplete. The complete question is as below:<em> Dominic and Eva are using the same type of stopwatches to measure the time it takes for a chemical reaction to occur. They each use the same stopwatch to measure the time. These are their results: </em>

<em>Dominic: 78 seconds </em>

<em>Eva: 81 seconds </em>

<em> Why are their results unreliable and can lead to a pseudoscientific claim? </em>

<em> They did not repeat their tests multiple times. </em>

<em>They used the same type of stopwatch. </em>

<em>They did not change the reactants in their chemical reactions. </em>

<em>Only one person should have collected the data.</em>

<u>Dominic and Eva's results are unreliable and can lead to a pseudoscientific claim because they did not repeat their tests multiple times. </u>

Repeating the test multiple times and finding the average of the measurement will minimize the chance of having error in the measurement and improve the accuracy of the outcome.

Thus, without repeated measurement, the reliability and the validity of the measurement would be in doubt.

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What is the half-life of a 12 g sample of radioisotope that decayed to 6 g in 28
Charra [1.4K]

Answer:

A. 28 years

Explanation:

Applying,

R = R'(2ᵃ/ⁿ).............. Equation 1

Where R = Original sample, R' = Sample left after decay, a = Total time taken to decay, n = half life.

From the question,

Given: R = 12 g, R' = 6 g, a = 28 years.

Substitute into equation 1 and solve for n

12 = 6(2²⁸/ⁿ)

12/6 = 2²⁸/ⁿ

2²⁸/ⁿ = 2

Equation the base,

28/n = 1

n = 28 years.

Hence the half-life is 28 years

4 0
3 years ago
A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the
wariber [46]

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

3 0
3 years ago
The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


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2 years ago
Which amount of a compound dissolved in 100g of water at the stated temperature represents a solution that is saturated
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40 g KNO, at 25°C

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3 years ago
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PIT_PIT [208]

Answer:

right

Explanation:

7 0
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