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Andrej [43]
3 years ago
14

Which of the following "spheres" is NOT involved in the water cycle?

Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
5 0
B is the correct answer.
The exosphere is the outermost region of the atmosphere the gradually merges out into space. The water cycle does not occur within this region.
harina [27]3 years ago
5 0
The answer is B. exosphere
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Why is it difficult for countries to reduce emissions of carbon dioxide
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Curbing global carbon dioxide emissions has been a challenge, primarily because they are being driven higher by countries with low per capita emissions.

Explanation:

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3 years ago
What is the element name for 2,2​
Strike441 [17]

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Helium

Explanation:

6 0
3 years ago
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Bleach is a 0.750 M solution of sodium hypochlorite. What volume, in litres, would contain 120.3 g of sodium hypochlorite?
Lady bird [3.3K]

Answer:

2.15 L

Explanation:

M(NaOCl) = 23.0 + 16.0 + 35.5 = 74.5 g/mol

120.3 g *1 mol/74.5 g = 1.615 mol NaOCl

0.750 M = 0.750 mol/L

1.615 mol * 1L/0.750 mol = 2.15 L

4 0
3 years ago
The molecular mass of sodium oxide (Na2O) is
yuradex [85]
<span>The molecular mass of sodium oxide (Na2O) is A. 61.97894. The molecular mass of a molecule (Mr) is the sum of atomic masses of its atoms (Ar). The molecular mass of sodium oxide is: Mr(Na2O) = 2 * Ar (Na) + Ar(O). From the periodic table, Ar(Na) = 22.989769 and Ar(O) = 15.9994. The molecular mass of sodium oxide is: Mr(Na2O) = 2 * 22.989769 + 15.9994 = 45.979538 + 15.9994 = 61.97894.</span>
6 0
3 years ago
A sample of gas occupies 2.30 L at 825 mmHg and 70.0°C. What is its volume at STP
Vladimir [108]

Answer:

V₂ = 2.0 Liters at STP conditions

Explanation:

Solving problem using the combined gas law

Given:

Case I Conditions           Cast II Conditions

P₁ = 825mmHg                P₂ = 760mm

V₁ = 2.30 Liters                V₂ =  ?  

T₁ = 70°C + 273 = 343K    T₂ = 0°C = 273K                  

Substitute into combined gas law assuming moles of gas remains constant; solve for unknown volume under case 2 conditions

P₁·V₁/n₁·T₁ = P₂·V₂/n₂T₂ => V₂ = P₁·V₁·T₂ / P₂·T₁  => note: in this solution, moles of gas remains constant as is disregarded in final calculation.

V₂ = (825mm)(2.3L)(273K) / (760mm)(343K) = 1.987 Liters (calculator answer) ≅ 1.9 Liters (2 sig figs based on given volume (V₁)

V₂ = 1.987 Liters ≅ 2.0 Liters (2 sig figs based on given volume (V₁)                    

6 0
2 years ago
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