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2 years ago

Solve each system by substitution.

Mathematics

1 answer:

mariarad [96]2 years ago

5 0

Answer:

1) (x, y) = (1, 8)

2) (x, y) =(-2, -4)

3) (x, y) = (3, -1)

Step-by-step explanation:

1) Given the equations;

7x+2y =23 .... 1

6x+y= 14 .... 2

From 2; y = 14-6x

Substitute into 1;

From 1; 7x+2y =23

7x + 2(14-6x) = 23

7x + 28 - 12x = 23

-5x = 23 - 28

-5x = -5

x = 5/5

x = 1

Substitute x = 1 into y = 14-6x

y = 14 - 6 (1)

y - 14 - 6

y = 8

Hence (x, y) = (1, 8)

2) Given

y=-4

y=-3x-10

We will simply equate bith expression and get x;

-3x - 10 = -4

-3x = -4 + 10

-3x = 6

x = 6/-3

x = -2

Hence the solution is (-2, -4)

3) Given the equation

y=-3x+8

y=5x-16

Equate both expressions;

-3x + 8 = 5x - 16

-3x - 5x = -16 - 8

-8x = -24

x = 24/8

x = 3

Substitute x = 3 into y=-3x+8

y = -3(3) + 8

y = -9 + 8

y = -1

Hence the solution (x, y) = (3, -1)

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Answer:

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Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

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Given G(4,3), H(1,0)

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Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

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Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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