The larger the piece the longer it will take to break down. This is because it has more mass that needs to be broken down.
To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area.
Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:
1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour
It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour.
Answer:
D. solid candle wax near the flame melts as the candle burns.
Answer:
a.
Explanation:
Assuming that Liquid X is considered to possess a greater viscosity as well as higher surface tension than liquid Y. Then, liquid X will tend to harbour more pressure inside the liquid.
In addition to that, the greater the surface tension, the greater the force required to expand the liquid's surface area.
This in turn makes the force required to make the loop 5% wider to be greater in FX rather than FY.
Thus, option a is the correct answer.
Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) × ( Mw )
Explanation:
sample:
∴ m = 15.00 g
a) atoms Pb = ?
⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
⇒ atoms Pb = 4.3595 E22 amu
b) relationship:
∴ 1 mol (n) ≡ 6.022 E23 amu......(1)
∴ mass (g) ≡ (Mw)×(n)
⇒ n = g / Mw..........(2)
∴ Mw: molecular weight
(1) = (2):
⇒ g / Mw ≡ 6.022 E23 amu
⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )
