Describes thesteps involved inа sampling operation

Chemistry

1 answer:

STALIN [3.7K]3 years ago

4 0

Explanation:

The minimum sampling rate allowed by the sampling theorem (fs = 2W) is called the Nyquist rate ... systems involving the use of continuous time functions of finite bandwidth. ... The sampling process is usually described in a time domain. This is an operation that is basic to digital signal processing and digital communication ...

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One problem with elimination reactions is that mixtures of products are often formed. For example, treatment of 2-bromo-2-methyl

NikAS [45]

Answer:

Structures are given below.

Explanation:

Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
H atoms adjacent to Br will be eliminated.
2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
Structure of alkenes are given below.

5 0

3 years ago

Precipitation _____. occurs equally all over the globe. is the change in state from a gas to a liquid. happens when ice changes

babunello [35]

Precipitation exceeds evaporation over the land.

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3 years ago

How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr

pickupchik [31]

Answer: There are $1.469 \times 10^{23}$ molecules present in 7.62 L of $CH_4$ at $87.5^{o}C$ and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = $87.5^{o}C = (87.5 + 273) K = 360.5 K$

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

$722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm$

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol$

According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.