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DochEvi [55]
3 years ago
15

Balance the following chemical equation by providing the correct coefficients HBr+Ba(OH)2 ———— BaBr2+H2O

Chemistry
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

2HBr + Ba(OH)2 = BaBr2 + 2H20

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If an acid is added to different samples of buffered water, the sample with the
Helen [10]

Answer:

<h3><u>A). react with acid that is added and make a base.</u></h3>

explanation:

<em>Buffer solutions resist a change in pH when small amounts of a strong acid or a strong base are added.</em>

3 0
2 years ago
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1) Consider this row in the periodic table. What changes can you predict based on what information is provided by the boxes for
bearhunter [10]

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B) As you move across the row, the number of electrons increases and reactivity also increases.

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The periodic table is arranged in a way that if you go across a period, the number of protons, neutrons, and electrons in an element increases. In terms of reactivity, the most reactive elements are the ones which have a high electronegativity. The electronegativity of the elements increases as you travel to the right and upwards on the periodic table.

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2 years ago
33 grams of NH4NO3 will produce how many grams of water
Leni [432]

Answer:

66 grams

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8 0
3 years ago
How does a chemist count the number of particles in a given number of moles of a substance?
jolli1 [7]
The chemist the count the number of particles (Atoms, Molecules or Formula Unit) in a given number of moles of a substance by using following relationship.

                              Moles  =  # of Particles / 6.022 × 10²³

Or,

                              # of Particles  =  Moles × 6.022 × 10²³

So, from above relation it is found that 1 mole of any substance contains exactly 6.022 × 10²³ particles. Greater the number of moles greater will be the number of particles.
8 0
3 years ago
At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu
mariarad [96]
According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M
7 0
3 years ago
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