All categories

3 years ago

draw an arrow from each box to the correct part of the photo then tell your reason for each choice in your boxes

Physics

1 answer:

Vilka [71]3 years ago

8 0

Answer:

we need the pic love

You might be interested in

If the weight of an object is greater than the weight of the water that it displaces, which is true? 1.the object will float bec

abruzzese [7]

2) Option B...............................

8 0

4 years ago

Read 2 more answers

The Venn diagram compares protons with neutrons. Which shared property belongs in the region marked "B"?

telo118 [61]

is there any choices?

4 0

3 years ago

Read 2 more answers

(03.05 LC)

Lynna [10]

Honed I don’t know where the question is

7 0

3 years ago

Read 2 more answers

An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on th

Evgen [1.6K]

Answer:

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

Explanation:

FOR SUV:

$ac_{suv} = \frac{mv^2}{r}\\$

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

$ac_{suv} = \frac{6000\ vo^2}{r}\\$ ---------------- equation (1)

FOR CAR:

$ao = \frac{mv^2}{r}\\$

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

$ao = \frac{2000\ vo^2}{r}\\$ --------------------- equation (2)

Dividing equation (1) by eq(2):

$\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao$

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

8 0

3 years ago

A vessel is filled with a liquid of density 1900 kg/m3 . There are two holes (one above the other) in the side of the vessel. Li

FromTheMoon [43]

Answer:

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity = 9.8 m/s²

the speed at each point

$v = \sqrt{2gh}$

for upper hole $v = \sqrt{2\times 9.8 \times 19}$

v = 19.29 m/s

lower hole $v = \sqrt{2\times 9.8 \times 117}$

v = 47.88 m/s

The path for each is parabolic

x = v t

$y = \dfrac{1}{2}gt^2$

$y = \dfrac{1}{2}g(\dfrac{x}{v})^2$

$y = \dfrac{gx^2}{2v^2}$

we get

upper hole

$y = \dfrac{9.8\times x^2}{2\times 19.29^2}= 0.0132 x^2$ lower hole

$y= \dfrac{9.8\times x^2}{2\times 47.88^2}=0.00214x^2$ y for upper hole = 80 + y for lower hole

$0.0132 x^2= 98 + 0.00214 x^2$

$0.0082 x^2 = 98$

x = 109.32 meters

110 meters is the distance where they will intersect

4 0

3 years ago