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Artist 52 [7]
2 years ago
14

Can you provide an example for both fission and fusion

Chemistry
1 answer:
dsp732 years ago
7 0
Fission energy is gained by splitting apart heavy atoms fusion is combining light atoms
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A solution has a [OH-] of 1 x 10^-12 M. What is the [H3O+] of the solution?
Yakvenalex [24]
First, lets find the pOH
pOH=-log[OH] ----> pOH=-log[1x10^-12] ----->pOH=12
Now we can find the pH
14-12=2
Now we can use the pH=-log[H3O] to find the hydrogen ion concentration
2=-log[H3O] ------>[H3O]=1.0 x 10^-2
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2 years ago
What's a beaker with a hole in it where a tube can be inserted to be connected to another beaker called?
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its in g,oogle

Explanation:

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3 years ago
All scientists try to base their conclusions on _____.
crimeas [40]
They try to base their conclusions off of data and measurements of which they should record from conducting experiments
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3 years ago
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Question 2 (1 point)<br>At the center of the atom is the electron.<br>True<br>False​
Stells [14]

Answer:

False the electrons are on the outside of the atoms

Explanation:

5 0
3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
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