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The reaction of formation of sulfur trioxide SO₃ from sulfur dioxide SO₂ is very slow because rate of reaction is very slow at room temperature.
WHAT IS REACTION FORMATION ?
Reaction Formation is the fixation in consciousness of an idea, affect, or desire that is opposite to a feared unconscious impulse.
WHAT IS RATE OF REACTION ?
The Rate of Reaction or Reaction Rate is the speed at which reactants are converted into products. When we talk about chemical reactions, it is a given fact that rate at which they occur varies by a great deal. Some chemical reactions are nearly instantaneous, while others usually take some time to reach the final equilibrium.
Thus, the reaction of formation of sulfur trioxide SO₃ from sulfur dioxide SO₂ is very slow because rate of reaction is very slow at room temperature.
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Na2SO4 -> 0.5 mol
Na+ ions= 0.5 x 2 = 1
SO4(2-) = 0.5
conc of Na+ = 1 / 1.33 = 0.75
conc. of SO4 ion = 0.5 / 1.33 = 0.37
Answer:
the acceleration i think is 10
Explanation:
5x10=50
Answer:
312 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.
Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:
Mole of O₂ = 9.75 moles
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mole = mass / Molar mass
9.75 = Mass of O₂ / 32
Cross multiply
Mass of O₂ = 9.75 × 32
Mass of O₂ = 312 g
Thus, 312 g of O₂ were obtained from the reaction.