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vichka [17]
3 years ago
5

Another metal phosphate is cobalt phosphate. It will behave similar to calcium phosphate in an acid solution. What is the net io

nic equation including phases for CoPO4(s) dissolving in H3O^+(aq)?
Chemistry
2 answers:
ryzh [129]3 years ago
8 0
We are given with
Cobalt phosphate - CoPO4

We are asked for the net ionic equation for the phosphate dissolving in H3O+

The net ionic equation is
CoPO4 (s) + H3O+ (aq) ----->  HPO42- (aq) + Co3+ (aq) + H2O *(l)
Sidana [21]3 years ago
7 0

Answer: The equation is given below.

Explanation:

Calcium phosphate does not dissolve in water but in acid it does.Similarly cobalt phosphate is also soluble in acidic solution as it get dispersed in the acid solution.

CoPO_4(s)+H_3O^(aq)+\rightarrow HPO_{4}^{2-}(aq)+Co^{3+}(aq)+H_2O(l)

When cobalt phosphate dissolves in acidic solution as it get strongly attracted by the acid molecules and dissociates into cobalt(III) ions, hydrogen phosphate and water molecule.

Hence, the net ionic equation for cobalt phosphate in hydronium ion is given above.

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What is the pH of a 3.5 x 10-^6 M solution of HCl?
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Answer:

5.46

Explanation:

From the question,

pH this can be defined as the acidity or alkalinity of a solution.

The expression for pH is given as

pH = -log(H⁺)...................... Equation 1

Where H⁺ = Hydrogen ion of HCL

Given: H⁺ = 3.5×10⁻⁶ M

Substitite this value into equation 1

pH = -log(3.5×10⁻⁶)

pH = 5.46

Hence the pH of HCl is 5.46

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3 years ago
Name the three states of matter, and the<br> physical changes that occur between them.
Nataly [62]

Answer:

Solid, Liquid, Gas

Solid to Liquid - Melting

Solid to Gas - Sublimation

Liquid to Solid - Freezing

Liquid to Gas - Vaporization

Gas to Solid - Deposition

Gas to Liquid - Condensation

Explanation:

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Why don't we see a lot of stars in day time?
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Explanation:

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An oily liquid with a cheesy, waxy odor like that of goats or other barnyard animals is caproic acid, a compound containing carb
Zinaida [17]

The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

  • Mass of H₂O = 20.99 g
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 4

Mass of H = 0.44 g

How to determine the mass of O

  • Mass of compound = 4.30 g
  • Mass of C = 2.67 g
  • Mass of H = 0.44 g
  • Mass of O =?

Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

Mass of O = 1.19 g

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

Learn more about empirical formula:

brainly.com/question/9459553

#SPJ1

6 0
1 year ago
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