Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.
Answer:
The new volume is 5.913*10^4 L
Explanation:
Step 1: Write out the formula to be used:
Using general gas equation;
P1V1 / T1 =P2V2 /T2
V2 = P1V1T2 / P2T1
Step 2: write out the values given and convert to standard unit's where necessary
P1 = 0.995atm
P2 0.720atm
V1 = 5*10^4 L
T1 = 32°C = 32+ 273 = 305K
T2 = -12°C = -12 + 273 = 261K
Step 3: Equate your values and do the calculation:
V2 = 0.995 * 5*10^4 * 261 / 0.720 * 305
V2 = 1298.475 * 10^4 / 219.6
V2 = 5.913 * 10^4 L
So the new volume of the balloon is 5.913*10^4 L
Answer:
1. the process of plants taking in sunlight and creating oxygen
2. outputs are oxygen
3. inputs are sunlight
Explanation:
I really hope this helps I’ve been there too and I’m just doing this so I get the 20 words and I have the picture
Answer:
The molarity (M) of the following solutions are :
A. M = 0.88 M
B. M = 0.76 M
Explanation:
A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.
Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)
= 27 + 3(16 + 1)
= 27 + 3(17) = 27 + 51
= 78 g/mole
= 78 g/mole
Given mass= 19.2 g/mole


Moles = 0.246

Volume = 280 mL = 0.280 L

Molarity = 0.879 M
Molarity = 0.88 M
B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr
Molar mass of KBr = 119 g/mole
Given mass = 235.9 g

Moles = 1.98
Volume = 2.6 L


Molarity = 0.762 M
Molarity = 0.76 M