The mass of the reactants and the mass of the products are no equal.
According to the equation of molarity:
Molarity= no.of moles / volume per liter of Solution
when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L
by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
= 0.58 * 0.150 = 0.087 Moles
Answer:
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
Explanation:
An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.
In this reaction, aqueous sodium hydroxide reacts with aqueous formic acid to form sodium formate and water.
1. Molecular equation
HCHO₂(aq) + NaOH(aq) ⟶ NaCHO₂(aq) + H₂O(ℓ)
2. Ionic equation
Sodium hydroxide and sodium formate are soluble ionic compounds, so we write them as hydrated ions.
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
Answer:
N₂H₆
Explanation:
A 1.000 g sample of nitrogen combined with a 0.0720 g sample of hydrogen to form N₂H₂ .
1.000 g of nitrogen combines with 0.2160 g of hydrogen in the next compound .
In this compound the component of nitrogen remains the same but the component of hydrogen becomes .2160 / .0720 = 3 times .
Hence component of hydrogen in the new compound will change from
H2 to H6 .
Hence the chemical formula of new compound will be
N₂H₆ .
