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icang [17]
3 years ago
13

Beth's summer vacation lasted 81 days. At the beginning of her vacation, she spent some time at soccer camp, 2 days at her grand

mother's house, and 11 days visiting Glacier National Park with her parents. She then had 40 vacation days remaining.
How many weeks did Beth spend at soccer camp?
Mathematics
2 answers:
Tasya [4]3 years ago
7 0

Answer: 4 weeks

Step-by-step explanation: 2+11=13

13+40=53

81-53=28

28÷7=4

i hope this helped !

enyata [817]3 years ago
4 0

Answer:

the answer is 4

Step-by-step explanation:

81 minus 28 minus 2 minus 11 equal 40 28 divide 7 is 4

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Can someone help pls.
kap26 [50]

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

8 0
2 years ago
Read 2 more answers
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
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4 years ago
Caffeine Castle buys bulk coffee to sell. The cost of 5 pounds of imported coffee is $60. What is the unit rate in cost per poun
katovenus [111]
Hey there! :) The answer to your question is $12 per pound. To find a unit rate you divide $60/5= $12. To double-check, 1 pound is $12, 2 pounds is $24, 3 pounds is $36, 4 pounds is $48, and lastly 5 pounds is $60. I hope you have a great day, and keep smiling! :D Also hoped I helped! ;)
8 0
3 years ago
Hi... can you tell me is this formula is right or wrong?? ​
Llana [10]

Answer:

this formula is right

6 0
3 years ago
0.679 what is the value of the number 6 digit
TiliK225 [7]

Answer:

6 tenths or 0.6, I hope this is what you mean.

Step-by-step explanation:


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