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3 years ago

Where is the distance on a position time graph

Physics

1 answer:

S_A_V [24]3 years ago

4 0

Answer:

The distance represents the difference of the first position and last position of the body.

Explanation:

For example, if y axis represents the position axis, and the first position is 3, second 9 we can see that the distance is a (positive) projection of one position into another. 9-3=6

Hope this helps.

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A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the

MArishka [77]

Answer:

The the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

Explanation:

From the question we are told that

The width of the slit is $D = 0.3 \ mm = 0.3 *10^{-3} \ m$

The wavelength is $\lambda = 254 \ nm = 254 *10^{-9} \ m$

The angle is $\theta = 11^o$

The intensity of at $11^o$ to the axis in terms of the intensity of the central maximum. is mathematically represented as

$I_c = \frac{I}{I_o} = [ \frac{sin \beta }{\beta }] ^2$

Where $\beta$ is mathematically represented as

$\beta = \frac{D sin (\theta ) * \pi}{\lambda }$

substituting values

$\beta = \frac{0.3 *10^{-3} sin (11 ) * 3.142}{254 *10^{-9} }$

$\beta = 708.1 \ rad$

$I_c = \frac{I}{I_o} = [ \frac{sin (708.1) }{(708.1)}] ^2$

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

6 0

4 years ago

Does anyone know what the Diaphragm on the microscope does?

steposvetlana [31]

Answer:

Diaphragm or Iris: Many microscopes have a rotating disk under the stage. This diaphragm has different sized holes and is used to vary the intensity and size of the cone of light that is projected upward into the slide.

Explanation:

6 0

4 years ago

Letting D D represent the maximum displacement, the extremes of the block's motion are at position A, where x = − D x=−D, and at

Ksju [112]

Answer:

The answer is at x = 0, which represents position B

Explanation:

The full question is:

"A block is attached to a horizontal spring and set in a

simple harmonic motion, as shown from above in the figure. When the spring is relaxed, the block is a position B, where the displacement x from the equilibrium position is 0. Letting D represent the maximum displacement, the extremes of the block's motion are at position A, where x= -D, and at position C, where x= D.

At what point in the motion is the speed of the block at its maximum?"

And you can see the figure on the attached file.

Simple Harmonic motion equations

We can start from the equation that describes the position that is

$x(t)=D \sin\left(\omega t)$

Here D stands for the amplitude which is the maximum displacement, and $\omega$ is the angular velocity, thus we can find the derivative to find the velocity equation, so we get

$v(t)=D \omega \cos (\omega t)$

And we can find the derivative again to find the acceleration.

$a(t) = -D\omega^2 \sin (\omega t)$

Maximum speed

We reach the maximum speed when the acceleration equation is equal to 0,

$a(t) =0\\-D\omega^2 \sin (\omega t)=0$

Thus it happens when

$\sin (\omega t)=0$

So if we replace that on the position equation we get

$x(t)=D \sin(\omega t) \\x(t)=D(0)\\x(t)=0$

Thus the position where the speed of the block is at at its maximum is when it is going back to the origin, that is x = 0, so point b.

7 0

3 years ago

Explain why open pipes are preferred to closed pipe in the production of music-

tatuchka [14]

Answer:

The frequencies of sounds made by these two types of instruments are different because of the different ways that air will move at a closed or open end of the pipe. Open pipes do not produce superior tone than closed (or stopped) pipes, therefore different types of pipes are used to produce different tonal qualities.

Explanation:

8 0

3 years ago

There are two nearby point sources, each emitting a light wave of frequency f. When the frequency f is increased, how will the d

Degger [83]

Answer:

An increase in frequency will cause an increase in the number of lines per centimeter and a smaller distance between each consecutive line. That is the distance between each trough

Explanation:

This is because higher frequency light source should produce an interference pattern with more lines per centimeter in the pattern and a smaller spacing between lines.

6 0

3 years ago