Answer:
84.30 mm Hg
Explanation:
In 100 cm³ of solution we have: 40 cm³ C6H6 and 60 cm³ CCl4. Given the densities we can calculate their masses and number of moles, and since by Raoult´s law
Ptotal = XAPºA + XBPºB
where XA= mol fraction =na/(na +nb) and PºA vapor pressure pure of pure component A
m C6H6 = 40 cm³ x 0.87865 g/cm³ = 35.146 g
mol C6H6 = 35.146 g/ 78.11 g/mol = 0.45 mol
mass CCl4 = 60 cm³ x 1.5940 g/cm³ = 95.640 g
mol CCl4 = 95.640 g / 153.82 g/mol = 0.62 mol
mol tot = 1.07
XC6H6 = 0.45/ 1.07 = 0.42 XCCl4 = 0.62/1.07 =0.58
Ptot (mmHg) = 0.42 x 74.61 + .58 x 91.32 = 84.30 mmHg
It would be 20 give me bravest
