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svlad2 [7]
3 years ago
5

Which of the following changes will decrease the rate of collisions between gaseous molecules oftype A and B in a closed contain

er?
A. decrease the volume of the container
B. increase the temperature of the system
C. add A molecules
D. take away B molecules
E. add an accelerating catalyst
Chemistry
1 answer:
Leni [432]3 years ago
4 0
D - take away B molecules
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Which diagram above has 4 valence electrons?
Gemiola [76]

Answer:

answer A has four valence electrons

Explanation:

The outer shell has 4 electrons, which are considered the valence electrons

8 0
3 years ago
Give 3 examples of solutions, suspensions and colloids..
Vlad [161]
  • <u>Some examples of solutions</u><u>"</u><u>:</u><u>"</u><u> are salt water, rubbing alcohol, and sugar dissolved in water.</u>

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5 0
3 years ago
Read 2 more answers
Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of NaN_3

\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}

Molar mass of NaN_3 = 65.01 g/mole

\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

n = number of moles N_2 = 0.466 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0
3 years ago
Porque el agua reduce la temperatura alta?
Naya [18.7K]
Porque la temperatura de la agua es neutral
8 0
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Where two air masses and do not mix
yulyashka [42]
When two air masses meet together, the boundary between the two is called a weather front. At a front, the two air masses have different densities, based on temperature, and do not easily mix. One air mass is lifted above the other, creating a low pressure zone.
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3 years ago
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