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3 years ago

What volume of silver metal will weigh exactly 2500.0g. The density of the silver is 10.5 g/cm3

Chemistry

2 answers:

mrs_skeptik [129]3 years ago

7 0

Answer : The volume of silver metal is $238cm^3$

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

$Density=\frac{Mass}{Volume}$

Given :

Mass of a silver metal = 2500.0 grams

Density of silver metal = $10.5g/cm^3$

Now put all the given values in the above formula, we get the volume of silver metal.

$10.5g/cm^3=\frac{2500.0g}{Volume}$

$Volume=\frac{2500.0g}{10.5g/cm^3}$

$Volume=238cm^3$

Therefore, the volume of silver metal is $238cm^3$

pochemuha3 years ago

6 0

Density = mass/volume
From this equation we can also say:
Volume = mass/density
V = 2500.0g/10.5g/cm3
V = 238 cm3

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The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?

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The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

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The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

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= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

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Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?