your answer is B my friend
Answer:
The molarity will be "0.43 M" and molality will be "0.43 m".
Explanation:
Given that:
mass of NaCl,
= 25 g
Volume of solution,
= 1 L
Density of solution,
= 1 gm/cm³
Now,
The weight of solvent will be:
= 
= 
= 
The mole of NaCl will be:
= 
= 
= 
hence,
The molarity will be:
= 
= 
= 
The molality will be:
= 
=
= 
Hey there!
Given the reaction:
B + H⁺ => HB⁺
At half-equivalence point : [B] = [HB⁺]
=> [B] / [HB⁺] = 1
Henderson-Hasselbalch equation :
pH = pKa + log ( [B] ) / ( HB⁺)]
pH = 14 - pKb + log ( 1 )
pH = 14 - 7.95 + 0
pH = 6.05
Answer C
Hope that helps!
M(Ag)=12.5 g
Nₐ=6.022*10²³ mol⁻¹
n(Ag)=m(Ag)/M(Ag)
N=n(Ag)*Nₐ
N=Nₐm(Ag)/M(Ag)
N=6.022*10²³mol⁻¹*12.5g/107.868g/mol=6.97*10²²
A. 6.97 × 10²² atoms
One.
In organic chemistry, an electrophile<span> is a reagent attracted to electrons.</span>Electrophiles<span> are positively charged or neutral species having vacant orbitals that are attracted to an electron rich centre. It participates in a chemical reaction by accepting an electron pair in order to bond to a nucleophile.
</span>
Carbon attached to O is electrophylic.
