Answer:
The car's displacement during this time is 25.65 meters.
Explanation:
Given that,
Final velocity of the car, v = 4.5 m/s
Deceleration of the car, 
Let u is the initial speed of the car. It is given by :
u = 12.6 m/s
Let d is the car's displacement during this time. It can be calculated using second equation of motion as :
d = 25.65 meters
So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.
The answer is CH4, 2O2, ? CO2 H20.
In the reaction, the the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide. The little number written at the lower right after an atom (subscript) tells how many of that atom are in the molecule. The big number written in front of a molecule (coefficient) shows how many of that molecule there are. All the atoms in the products come from the atoms in the reactants.
The reactants are on the left side of the equation and the products are on the right. In the reaction, the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide
All the atoms in the reactants form the products so the mass of the reactants and the products is the same. No new atoms are created and no atoms are destroyed.
Answer:
It is about 490 Newtons. 490.3325 to be exact
Explanation:
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Answer:
7 m/s^2
Explanation:
Given that the jet is traveling 37.6 m/s when the pilot receives the message.
And it takes the pilot 5.37 s to bring the plane to a halt.
Acceleration of the plane can be calculated by using first equation of motion
V = U - at
Since the plane is going to stop, the final velocity V = zero.
And the acceleration will be negative
Substitute all the parameters into the formula
0 = 37.6 - 5.37a
5.37a = 37.6
Make a the subject of formula
a = 37.6 / 5.37
a = 7.0 m/s^2
Therefore, the acceleration of the plane to bring the plane to a halt is 7 m/s^2
Answer:
500 kg
Explanation:
It is given that,
The mass of a open train car, M = 5000 kg
Speed of open train car, V = 22 m/s
A few minutes later, the car’s speed is 20 m/s
We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :
initial momentum = final momentum
Let m is final mass
MV=mv
Water collected = After mass of train - before mass of train
= 5500 - 5000
= 500 kg
So, 500 kg of water has collected in the car.
