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2 years ago

13

When a space shuttle was launched, the astronauts onboard experienced an acceleration of 29.0 m/s2 . If one of the astronauts ha

d a mass of 60.0 kg, what net force in newtons did the astronaut experience?

1 answer:

yan [13]2 years ago

6 0

F = m*a when F is force
m is mass and a is acceleration
F = 60 kg * 29 m/s2
F = 1740 N

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Question 7 of 25

tiny-mole [99]

Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

2Na + MgCl₂ → 2NaCl + Mg

Explanation:

A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation

Among the given chemical reactions, we have;

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

In the above reaction;

The number of phosphorus, P, on either side of the equation = 2

The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na, one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

6 0

2 years ago

Why is science always changing

Anastaziya [24]

Answer:

Science is changing because little by little scientists descover new things.

Explanation:

Discovery

Hope this helps:)

8 0

3 years ago

Read 2 more answers

If the specific surface energy for magnesium oxide is 1.0 J/m2 and its modulus of elasticity is (225 GPa), compute the critical

alexdok [17]

Answer:

The critical stress required for the propagation of an initial crack $\sigma_{c}$ = 21.84 M pa

Explanation:

Given data

Modulus of elasticity E = 225 × $10^{9}$ $\frac{N}{m^{2} }$

Specific surface energy for magnesium oxide is $\gamma_{s}$ = 1 $\frac{J}{m^{2} }$

Crack length (a) = 0.3 mm = 0.0003 m

Critical stress is given by $\sigma_{c}^{2} }$ = $\frac{2 E \gamma}{\pi a}$ -------- (1)

⇒ 2 E $\gamma_{s}$ = 2 × 225 × $10^{9}$ × 1 = 450 × $10^{9}$

⇒ $\pi$ a = 3.14 × 0.0003 = 0.000942

⇒ Put these values in equation 1 we get

⇒ $\sigma_{c}^{2} }$ = $\frac{450 }{0.000942} 10^{9}$

⇒ $\sigma_{c}^{2} }$ = 4.77 × $10^{14}$

⇒ $\sigma_{c}$ = 2.184 × $10^{7}$ $\frac{N}{m^{2} }$

⇒ $\sigma_{c}$ = 21.84 $\frac{N}{mm^{2} }$

⇒ $\sigma_{c}$ = 21.84 M pa

This is the critical stress required for the propagation of an initial crack.

4 0

3 years ago

The alignment of atoms where the north poles face one way and the south poles face the opposite way is also known as which of th

Pepsi [2]

The answer is B. Domain
When the atoms point to the same direction and aligned with one another, It will form a magnetic material in which magnetization is in a uniform direction
This alignment usually happens stimunaleously due to exchange interaction that caused by a response to an external field.

3 0

2 years ago

Two identical masses, A and B, slide down frictionless ramps, both starting at a height of 3M above the ground. Object A slides

balu736 [363]

Answer: c. Neither, they have the same speed.

In both the cases, there will be work done by the gravitational force. Since, the gravitational force is a conservative force, its work done does not depend on the path as it only depends on the initial and final position of the objects. Since, the initial and final positions are same for both the objects, the work done by gravitational force will be same in both the cases.

Hence, Work done by gravitational force = Change in the kinetic energy

So, the kinetic energy will be same for both the object.

Since, the masses are same: Kinetic energy = $\frac{1}{2}mv^2$

Hence, the speed will also be same for both the objects.

Correct option: C

3 0

3 years ago