3 years ago

He is best known for publishing an almanac based on my astronomical calculations. Who is it?

Physics

1 answer:

slega [8]3 years ago

5 0

Benjamin Banneker did this in 1792. Hope this helps

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$E = mc^2$

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now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

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