Question

An object is placed 5.00 cm beyond the focal point of a convex lens whose focal length is 10.0 cm. If the object height is 3.0 cm, calculate the image height.
A. 150
B. -6.0
C. 1.5

What is the orientation of the image? Erect or inverted?

Answer 1

Answer:

The height of the image is, h' = 6.0 cm

The image is erect.

Explanation:

Given data,

The object distance, u = -5 cm

The focal length of convex lens, f = 10 cm

The object height, h = 3 cm

The lens formula,

                      $\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

                      $\frac{1}{10}=\frac{1}{v}-\frac{1}{-5}$

                      $\frac{1}{v}=\frac{1}{10}-\frac{1}{5}$

                      v = -10 cm

The magnification factor of lens

                     $m=\frac{-10}{-5}$

                     m = 2

                     $m=\frac{h'}{h}$

                     $h'=h\times m$

                     $h'=3\times 2$

                     h' = 6 cm

The height of the image is, h' = 6 cm

The image is erect.