Any ions with a charge (3+ ) has?

Burka [1]

C. Tetraphosphorus trisulfide

8 0

2 years ago

A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g

svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂ b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

Ni + Br₂ ⇒ NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

159.8 g of Br₂ --------------- 218.8 g of NiBr₂

37.3 g of Br₂ -------------- x

x = (37.3 x 218.8) / 159.8

x = 8161.24/159.8

x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

59 g of Ni ---------------- 159.8 g of Br₂

x ---------------- 37.3 g of Br₂

x = (37.3 x 59)/159.8

x = 2200.7/159.8

x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

= 54 g

5 0

3 years ago

A sample of gas occupying 350 mL at 25 C is cooled to -25 C. What volume will it occupy if the pressure is held constant?

leonid [27]

Answer:

I hac no ideasghjjbhnn

7 0

2 years ago

What atomic or hybrid orbitals make up the sigma bond between Cl and F in chlorine trifluoride, ClF3

Umnica [9.8K]

Answer:

sp³d¹ hybridization

Explanation:

Given Cl as central element with three F substrates ...

The VSEPR structure indicates 5 hybrid orbitals that contain 2 diamagnetic orbitals (non-bonded e⁻-pairs) and 3 paramagnetic orbitals (single, non-paired electron for covalent bonding with fluorine) giving a trigonal bypyrimidal parent with a T-shaped geometry.

Valence bond theory predicts the following during bonding:

Cl:[Ne]3s²3p²p²p¹3d⁰

=> [Ne]3s²p²p¹p¹d¹

=> [Ne]3(sp³d)²(sp³d)²(sp³d)¹(sp³d)¹(sp³d)¹

giving 3 ( [Cl](sp³d) - [F]2p¹ ) sigma bonds and 2 non-bonded pairs on Cl.

Note the following images:

Non-bonded electron pairs are in plane of parent geometry and Fluorides covalently bonded to central element Chloride forming the T-shaped geometry.

7 0

2 years ago

Pure acetic acid (hc2h3o2) is a liquid and is known as glacial acetic acid. calculate the molarity of a solution prepared by dis

Alexandra [31]

In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:

Mass = volume * density

Mass = 50 * 1.05
Mass = 52.5 grams

Moles = mass / molecular weight

Moles = 52.5 / 60.05
Moles = 0.874 mol

Next, we know that the molarity of a solution is:

Molarity = moles / liter
Molarity = 0.874 / 0.5

Molarity = 1.75 M

3 0

2 years ago

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