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PSYCHO15rus [73]
2 years ago
7

Molar mass is measured in units of

Chemistry
1 answer:
blsea [12.9K]2 years ago
5 0
D. grams/ mole.
........
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The rate constant for the first-order decomposition at 45 °C of dinitrogen pentoxide, N2O5, dissolved in chloroform, CHCl3, is 6
weeeeeb [17]

Answer:

Rate of the reaction= 9.92× 10^-5 M² min-1

Explanation:

Using the equation of reaction

2N2O5 ⟶ 4NO2+O2

Rate = k[N2O5]²

From the question k= 6.2×10-4

[N2O5]= 0.4

Rate = 6.2×10-4[0.4]²= 9.92×10-5M² min-1

7 0
3 years ago
The nucleus of a fluorine atom has a charge of? <br><br> A. +19<br> B. 0<br> C. +9<br> D. +1
posledela

Answer:

A fluorine atom has nine protons and nine electrons, so it is electrically neutral. If a fluorine atom gains an electron, it becomes a fluoride ion with an electric charge of -1.

7 0
3 years ago
What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy
meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation  </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

The equation is:  

 \tt \Delta U=Q+W

Energy owned by the system is expressed as internal energy (U)  

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

\tt \Delta E=-13+5=-8~kJ

6 0
2 years ago
On a graph , which type of line shows a direct proportion?
svetoff [14.1K]
C - straight line
.....................................................................................
5 0
2 years ago
Read 2 more answers
Given the reaction: A + B &lt;--&gt; C + D
Lady_Fox [76]

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }                                       <----- Equilibrium expression

K = \frac{[2 M] [2 M]}{[1 M] [1 M] }                                     <----- Insert molarities

K = \frac{4}{1  }                                                <----- Multiply

K = 4                                                <----- Divide

6 0
2 years ago
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