No units are provided in the data table, though one would usually assume that 0.244 is molarity of NaOH, and buret data of 14.7 is probably the final volume of NaOH in mL. No identification is given for the 38, but maybe this is the initial buret volume in mL.
If the buret was rinsed with water, it should have been left to dry for some time, or else the added water may slightly dilute the NaOH solution placed in it.
Hey there!:
Molar mass MgCl2 = 95.2110 g/mol
So:
1 mole MgCl2 -------------- 95.2110 g
moles MgCl2 ---------------- 319 g
moles MgCl2 = 319 * 1 / 95.2110
moles MgCl2 = 319 / 95.2110
=> 3.350 moles of MgCl2
Hope that helps!
3.52g BiCl3 × 1 mol BiCl3/ 315.34g BiCl3 × 3 mol Cl/ 2 mol BiCl3 × 70.906g Cl/ 1 mol Cl= 1.187 g Cl
