Answer:
Because iodine is a liquid, it has no melting point. Iodine is not an electrical conductor because each molecule consists of two iodine atoms connected by a covalent bond that cannot be stimulated sufficiently to transmit electrical energy.
Explanation:
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Answer:
The thermodynamic parameter which is of significance in this case is the 'Reduction Potential' for molecular bromine which is ~ +1.1 v vs N.H.E. In other words, it is a strong oxidizing agent. The bromine will oxidize sulfur compounds in which the valence of sulfur is lower than six to sulfate.
There are many possible reactions. Here is one possible example:
Na2 S2O3 + 4Br2 + 5 H2O = 2NaHSO4 + 8 HBr
Its C, Outermost Electrons.
Answer:
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
Explanation:
First equation:
The reactants propane and water react to form the products CO and H2
C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)
Second equation:
The products CO and H2 will react
CO(g) + H2O(g) → H2(g) + CO2(g)
We should multiply the equation by 3 (to equal the products of the first equation)
3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)
Add the second to the first equation:
C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
