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hoa [83]
3 years ago
7

What does it mean for an object to be dense?

Chemistry
1 answer:
Sedbober [7]3 years ago
4 0

Answer: Density is a measure

Explanation:  The more squashed together an object’s particles are, the denser it is.

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Explain how acid–base indicators can be used to determine the approximate pH of a substance.
mezya [45]
PH stands for potential hydrogen.
pH can be accurately tested using acid-based indicators since it is a part of the pH of something itself. (acid and bases) The indicators themselves work when the acidic properties of the indicator begins to dissolve and form ions which gives the color indicating the pH.


5 0
3 years ago
Please help fast!! I need someone to see if my answers are correct! If any are wrong please let me know what the correct answers
marta [7]

Yeah all of them are right :)

4 0
3 years ago
HELP ASAP 30 POINTS
allsm [11]

Answer:

Explanation:

Dind out

5 0
3 years ago
Read 2 more answers
#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
Murljashka [212]

Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

7 0
3 years ago
A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure
Ostrovityanka [42]

The volume did not change, it remained at 20 ml

<h3>Further explanation</h3>

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

\tt \dfrac{1\times 20}{273}=\dfrac{2\times V_2}{546}\\\\V_2=\dfrac{1\times 20\times 546}{273\times 2}\\\\V_2=20~ml

The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)

5 0
2 years ago
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