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Marta_Voda [28]
3 years ago
12

Please explainnnnnnnnnn

Chemistry
2 answers:
deff fn [24]3 years ago
7 0

Volume=10ml

Density=1.5g/ml

\boxed{\sf Density=\dfrac{Mass}{Volume}}

\\ \sf\longmapsto Mass=Density\times Volume

\\ \sf\longmapsto Mass=1.5(10)

\\ \sf\longmapsto Mass=15g

zysi [14]3 years ago
5 0
The answer is 15g
The mass of a substance when given the density and volume can be found by using the formula
Mass = Density x Volume
From the question
Density of chloroform=1.5 g/ml
Volume=10mL
We have
Mass=1.5x10
We have the final answer as
15g
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If .758 moles of gas occupy a volume of 80.6L, how many moles will occupy a volume of 270.9L?
egoroff_w [7]

Answer:

n₂ = 2.55 mol

Explanation:

Given data:

Initial number of moles = 0.758 mol

Initial volume = 80.6 L

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Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = initial number of moles

V₂ = Final volume

n₂ =  Final number of moles

now we will put the values in formula.

V₁/n₁ = V₂/n₂

80.6 L / 0.758 mol = 270.9 L/ n₂

n₂ = 270.9 L× 0.758 mol / 80.6 L

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4 0
3 years ago
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Oksi-84 [34.3K]

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3 years ago
A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of
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Answer:

108 kPa  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂             Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂      Divide each side by V₁

      p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?;                 V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the <em>pressure </em>

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)  

   = 122.2 kPa × 0.8542 × 1.0357

   = 108 kPa

4 0
3 years ago
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