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Orlov [11]
1 year ago
12

A 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦

above the horizontal. How long is the projectile in the air? The acceleration due to gravity is 9.8 m/s.
Answer in units of s.
Physics
1 answer:
Ann [662]1 year ago
5 0

By adding the time of flight at the top of the cliff and the time taken down the hill, the ball spent 2.72 s of time in air.

<h3>What is a Projectile ?</h3>

A projectile can be a stone or a ball or any object that can be projected. The object projected will take a trajectory path.

Given that acceleration due to gravity is 9.8 m/s and a 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦ above the horizontal. To know how long the projectile will be in the air, we will calculate the total time of flight at the top of the cliff and the time taken down the hill

Time of flight T = 2usinФ/g

Where

  • g = m/s²
  • Ф = 49°
  • h = 8.52 m
  • u = 9.1 m/s
  • t = ?
  • m = 0.87 kg

Substitute all the necessary parameters into the formula

T = (2 × 9.1sin49)/ 9.8

T = 13.74/9.8

T = 1.40 s

The time taken down the cliff can be found with formula

h = ut + 1/2gt²

where u = 0

8.52 = 0 + 1/2 × 9.8 × t²

8.52 = 4.9t²

t² = 8.52/4.9

t² = 1.738

t = √1.738

t = 1.32 s

Time for the projectile in the air = T + t

Time in air = 1.40 + 1.32

Time = 2.72 s

Therefore, the projectile will be in the air for 2.72 seconds long.

Learn more about Projectile here: brainly.com/question/24949996

#SPJ1

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Given that a car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The following are the given parameters

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